Question

Chris Nazarro had total travel expenses of $872. His transportation cost was $136. The hotel cost was $210 and business materials cost $500. If his lunch cost 30% of his dinner, how much was dinner to the nearest cent?

Answer 1

Answer:

$\ 20$

Step-by-step explanation:

Let

x-----> the cost of his lunch

y----> the cost of his dinner

we know that

$x+y=872-136-210-500$

$x+y=26$ -----> equation A

$x=0.3y$ ---> equation B

substitute equation B in equation A

$0.3y+y=26$

$1.3y=26$

$y=\ 20$ -----> the cost of the dinner