Answer:
ZnO(s) + 2HCl(aq) ------> ZnCl2(aq) + H2O(l)
Na2O(s) + 2HCl(aq) -----> 2NaCl(aq) + H2O(l)
Rb2O(s) + 2HCl(aq) -----> 2RbCl(aq) + H2O(l)
NiO(s) + 2HCl(aq) --------> NiCl2(aq) + H2O(l)
MgO(s) + 2HI(aq) -----> MgI2(aq) + H2O(l)
Na2O(s) + 2HI(aq) -----> 2NaI(aq) + H2O(l)
CaO(s) + 2HI(aq) ----> CaI2(aq) + H2O(l)
Explanation:
Let us recall that the oxides of metals are basic in nature. These basic metal oxides can react with acids to form salt and water only.
In the reactions above, HCl and HI were reacted with different metal oxides and the corresponding salts of each metal and water was formed as shown.
Answer: See below
Explanation:
n of CO2 = 0.364mmol
Mass of C = 0.364*12 = 4.368 mg
n of H2O = 184.37 = 0.243 mol
The compound has 2*0.243mmol of H
Mass of H = 0.486 mg
Mass of O = 10.68 − (4.368+0.486) = 5.826mg
Moles of O = 0.364
<u>C:H:O Ratios</u>
0.364 : 0.486 : 0.364
= 1 : 1.34 : 1
= 3 : 4 : 3
<u>So the empirical formula is C3H4O3,</u>
Empirical formula mass
= 88= 2 × Molar mass
<u>And the molecular formula is C6H8O6</u>
Explanation:
Cu + 2 AgNO3 → Cu(NO3)2 + 2 Ag
Cu is oxidized
Ag+ is reduced
Cu is the reducing agent
