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trapecia [35]
2 years ago
6

Martha ran 420 m, and Cole ran 60 m less than Martha. The distance Kate ran is right in the middle of Martha and Cole's distance

s. How far did Kate run?
Chemistry
1 answer:
prohojiy [21]2 years ago
8 0

Answer:

390 m

Explanation:

Martha ran 420 m

Cole ran 60 m less than Martha = 420 m - 60 m = 360 m

The distance Kate ran is right in the middle of Martha and Cole's distances

Kate distance = (420 + 360) / 2 = 780 / 2 = 390 m

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Answer:

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CONCLUSIONS: Suppose a student titrated a sample of monoprotic acid of unknown concentration using a previously standardized sol
Zolol [24]

Concentration of unknown acid is 0.061 M

Given:

Concentration of NaOH = 0.125 M

Volume of NaOH = 24.68 mL

Volume of acid solution = 50.00 mL

To Find:

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Solution: Concentration is the abundance of a constituent divided by the total volume of a mixture. The concentration of the solution tells you how much solute has been dissolved in the solvent

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3 0
1 year ago
The formulas for elements never contain a subscript true or not true
Andru [333]
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3 years ago
Question 9 of 10
aksik [14]

Answer:

The answer is B an open system allows energy and mass to move in and out of it

Hope it helps

7 0
1 year ago
The enthalpy of vaporization (ΔH°vap) of benzene is 30.7 kJ/mol at its normal boiling point of 353.3 K. What is ΔS°vap at this t
vazorg [7]

<u>Answer:</u> The correct answer is Option c.

<u>Explanation:</u>

Vaporization is defined as the physical process in which liquid particles get converted to gaseous particles.

Liquid\rightleftharpoons Gas

The value of standard Gibbs free energy is 0 for equilibrium reactions.

To calculate \Delta S^o_{vap} for the reaction, we use the equation:

\Delta S^o_{vap}=\frac{\Delta H^o_{vap}}{T}

where,

\Delta S^o_{vap} = standard entropy change of vaporization

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T = temperature of the reaction = 353.3 K

Putting values in above equation, we get:

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Hence, the correct answer is Option c.

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