There are four substances, A, B C and D. A and C are pure substances. They cannot be broken down into anything simpler by chemic
al methods. B consists of A and D, which are not chemically bonded together. D is a pure substance. We can decompose D into A and C using chemical methods. How would we classify substance A, C, and D?
A: Substances A and C are elements, because they are pure substances that bond together to make substance D and cannot be broken using chemical processes . Substance D is a mixture, because it is a pure substance made up of A and C.
B: Substances A and C are compounds, because they are pure substances that bond together to make substance D and cannot be broken using chemical processes . Substance D is a mixture, because it is a pure substance made up of A and C.
C: Substances A and C are elements, because they are pure substances that bond together to make substance D and cannot be broken using chemical processes. Substance D is a compound, because it is a pure substance made up of A and C.
D: Substances A, C, and D, are elements. All pure substances are elements.
A: Substances A and C are elements, because they are pure substances that bond together to make substance D and cannot be broken using chemical processes . Substance D is a mixture, because it is a pure substance made up of A and C.
B: Substances A and C are compounds, because they are pure substances that bond together to make substance D and cannot be broken using chemical processes . Substance D is a mixture, because it is a pure substance made up of A and C.
C: Substances A and C are elements, because they are pure substances that bond together to make substance D and cannot be broken using chemical processes. Substance D is a compound, because it is a pure substance made up of A and C.
D: Substances A, C, and D, are elements. All pure substances are elements.
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Answer: There are 0.006 moles of acid in the flask.
Explanation:
Given: = 21.35 mL,
= 0.150 M
= 25.0 mL,
= ?
Formula used to calculate molarity of is as follows.
Substitute the values into above formula as follows.
As molarity is the number of moles of a substance present in a liter of solution.
Total volume of solution =
= 21.35 mL + 25.0 mL
= 46.36 mL (1 mL = 0.001 L)
= 0.04636 L
Therefore, moles of acid required are calculated as follows.
Thus, we can conclude that there are 0.006 moles of acid in the flask.