Answer:
the only remote information i could find about this element was sodium
dicyanidoaurate(I)
sodium dicyanoaurate(1-)
Na[Au(CN)2]
sodium dicyanidoaurate(1-)
but as you see these go towards Na[Au(CN)2] not Na[Au(CN)4], so I will leave the rest up to you.
Have a good day.
Explanation:
https://pubchem.ncbi.nlm.nih.gov/compound/5460536
that is the website i found that off of
https://www.webqc.org/molecular-weight-of-Na%5BAu%28CN%294%5D.html
this one tells you the element names.
<span>.068443 mol/L
First we must find the molar mass of NaCl. We find the atomic mass of sodium and chlorine and add them:
Na: 22.9898
Cl: 35.453
22.9898 + 35.453 = 58.4428g/mol
The we find the number of mols contained in 400mg of NaCl:
.4g / 58.4428g/mol
.0068443 mol
Since 100mL is a tenth of a liter we can multiple the number of mols by ten:
.068443 mol/L</span>
The atomic mass<span> is </span>not<span> given as a </span>whole number<span> because it is a heavy average taken of all of an </span>atom's<span> isotopes found in nature relative to the </span>mass<span> of carbon-12.</span>
The atomic number is 6, you can also find out by the amount of electrons because, electrons and protons have the same charge.