Answer:
The number of moles of water will be produced when 8.0 moles of ethane are burned = 24.0 mol.
Explanation:
- It is a stichiometry problem.
- The balanced equation of burning ethane is:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
- It is clear that 2.0 moles of ethane (C₂H₆) burns in 7.0 moles of oxygen and produce 4.0 moles of CO₂ and 6.0 moles of H₂O.
<em><u>Using cross multiplication:</u></em>
2.0 moles of ethane produces → 6.0 moles of H₂O, from the stichiometry.
8.0 moles of ethane produces → ??? moles of H₂O.
- ∴ The number of moles of water will be produced when 8.0 moles of ethane are burned = (6.0 x 8.0) / (2.0) = 24.0 mol.
Answer:
no one can answer your question because you have shown no arrows.
Temperature
surface area
reactant concentration
Answer:
The molar mass of NaOH is 40.00 g/mol.
The number of moles of NaOH is equal to the ratio of its mass to molar mass.
The number of moles of NaOH =
40 g/mol
40 g
=1,000 mol
The molarity of NaOH solution is the ratio of number of moles of NaOH to total volume of solution in L.
M=
1 L
1 mol
=1 M
Explanation ;)
