Simple,
writing out the problem...

Simplify it...
-4x(6+5-1)
-4x(11-1)
-4x(10)
-40x
Making it look like...

Cancel out the common factors...
Thus making the answer:

.
Answer:
the decimal measuring system based on the meter, liter, and gram as units of length, capacity, and weight or mass. The system was first proposed by the French astronomer and mathematician Gabriel Mouton (1618–94) in 1670 and was standardized in France under the Republican government in the 1790s.
Step-by-step explanation:
Answer: 0.951%
Explanation:Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.
Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).
Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or
0.951%.
A random sample (Sample 1) of the Mercedes's average driving speed (km/h) is: 120, 142, 142, 165, 132, 130, 156, 136, 167, 139,
ziro4ka [17]
The median of Mercedes' speed is 144 km/h.
The median of Audi's speed is ~133,6 km/h.
Answer:
1) Amy and Kara are walking to the park to hangout for a while. On the way they pass a lake and a store.
2) Sara and Jake are heading to the movie theater for a romantic movie. On the way, they pass a duck pond.