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Finger [1]
3 years ago
14

The three vertices drawn on a complex plane at represented by 0+0i, 4+0i, and 0+3i. What is the length of the hypotenuse

Mathematics
1 answer:
tatuchka [14]3 years ago
6 0
Check the picture below

you can pretty much get the values for "a" and "b" from the grid.

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What is the term-to-term rule for this sequence: 64, 16, 4, 1, 0.25, …?
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Answer: 0.0625

Step-by-step explanation:

0.25/4

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On Friday,
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3 years ago
Assume that when adults with smartphones are randomly​ selected,41 ​% use them in meetings or classes. If 5 adult smartphone use
kotegsom [21]

Answer:

0.345

Step-by-step explanation:

Use binomial probability:

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

n = 5, r = 2, p = 0.41, and q = 0.59.

P = ₅C₂ (0.41)² (0.59)⁵⁻²

P = 0.345

3 0
3 years ago
Find the derivative of the function at P 0 in the direction of A. ​f(x,y,z) = 3 e^x cos(yz)​, P0 (0, 0, 0), A = - i + 2 j + 3k
Alik [6]

The derivative of f(x,y,z) at a point p_0=(x_0,y_0,z_0) in the direction of a vector \vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k is

\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}

We have

f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k

and

\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}

Then the derivative at p_0 in the direction of \vec a is

3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}

3 0
4 years ago
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