There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
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Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
Answer:
can you add a paper or more info to answer
Step-by-step explanation:
Answer:
I believe the answer is A
Please correct me if I am wrong
Answer:
(in order) #1
for the first one you have a vertical angle. Vertical angle is basically any 2 lines who intersect each other. The opposite sides will be congruent.
So in this case
2x+8 and 110 are oppostie sides.
2x+8=110
Which is x= 51
#2
For the second one you have supplementray angles
Now for supplementary angles its basically 2 angles added up that form a straight line And 180 degress is always the measure of a straight line. SO in this case we do
9x+12x+75=180
Which is x=5
#3
This is also a vertical angle pair and their congruent just like #1
So 5x+5=65
x=12
