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vladimir2022 [97]
4 years ago
11

Which would require a greater force -accelerating a 10g mass at 5ms-2 or a 20g mass at 2ms-2?

Physics
2 answers:
Trava [24]4 years ago
5 0
Force 1 = 10/1000 × 5 = 0.05 N
Force 2 = 20/1000 × 2 = 0.04 N

F1>F2

so the answer is Force 1
pav-90 [236]4 years ago
4 0
F= mass X speed

10g x 5
20x2


50n
40n
50>
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Please i need the answer asap
netineya [11]
50 because that is as fast as a car
5 0
3 years ago
A plane flies 446 km east from city A to city B in 43.0 min and then 939 km south from city B to city C in 1.10 h. For the total
NeTakaya

Answer:

(a) Magnitude is 1039 km

(b) Direction of the displacement is 64.59^{\circ} South of East

(c) Average velocity magnitude is 570.88 km

(d) The direction of average velocity is 64.59^{\circ} South of East

(e) Average speed is 759.34 km/h

Solution:

Distance moved from A to B in East direction, \vec{AB} = 446 km

Distance moved from B to C in South direction, \vec{BC} = - 939 km

Time taken to move from A to B, t = 43.0 min = 0.72 h

Time taken to move from B to C, t' = 1.10 h

Now,

(a) The magnitude of displacement of the plane is provided by AC as shown in fig 1 and can be given as:

AC = \sqrt{(AB)^{2} + (BC)^{2}}

AC = \sqrt{(446)^{2} + (- 939)^{2}} = 1039 km

(b) Direction of the displacement is given by:

tan\theta = \frac{\vec{BC}}{\vec{AB}}

\theta = tan^{- 1}(\frac{- 939}{\vec{446}}) = - 64.59^{\circ}

64.59^{\circ} South of East

(c) Magnitude of the average speed is given by:

v_{avg} = \frac{AC}{t + t'}

v_{avg} = \frac{1039}{1.82} = 570.88 km/h

(d) The direction of the average velocity is the same as that of the displacement, i.e., 64.59^{\circ} South of East.

(e) The average speed of the [plane is given by:

v'_{avg} = \frac{Total\ Distance\ Traveled}{Total\ Time}

v'_{avg} = \frac{446 + 939}{1.10 + 0.72} = 759.34 km/h

6 0
3 years ago
A bowling ball is launched off the top of a 240-foot tall building. The height of the bowling ball above the ground t seconds af
Vilka [71]

Answer:

V = (-32t +32) ft/s

The velocity of the bowling ball after t seconds is the time derivative of the position function s(t). To obtain the velocity from s(t) we simply differentiate s(t) with respect to t. That is

V = ds(t)/dt = -16×2t + 32×1 = -32t + 32.

When differentiating, you multiply the coefficient of each term in the equation with the power of the variable and then reduce the power by 1 just like above.

Explanation:

8 0
3 years ago
Thermal energy produced by friction cannot usually be used to do work. true/false
maria [59]
I believe the correct response would be true, thermal energy or heat that is produced by friction usually cannot be used to do work.
4 0
4 years ago
Read 2 more answers
PLS HELP I WILL GIVE BRAINLYEST!!!
Ede4ka [16]

Answer:

225

Explanation:

4 0
3 years ago
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