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RUDIKE [14]
3 years ago
9

One way to store energy is in the rotational motion of a flywheel, and some have proposed using such technology to power automob

iles. one unit is based on a 6.5-\(\rm kg\) flywheel in the shape of a hoop of radius 0.11 \(\rm m\) that spins as fast as 70000 \(\rm rpm\).
Physics
1 answer:
miskamm [114]3 years ago
4 0

Answer:

The store energy is 2113109.72 J.

Explanation:

Given that,

Radius = 0.11 m

Mass = 6.5 kg

Spins = 70000 rpm

Suppose we need to find how much kinetic energy is stored by the flywheel when it is rotating at its maximum rate

We need to calculate the moment of inertia

Using formula of moment of inertia

I=mr^2

Put the value into the formula

I=6.5\times(0.11)^2

I=0.07865\ kg-m^2

We need to calculate the rotational kinetic energy

Using formula of rotational kinetic energy

K.E=\dfrac{1}{2}I\omega^2

Put the value into the formula

K.E=\dfrac{1}{2}\times0.07865\times(70000\times\dfrac{2\pi}{60})^2

K.E=2113109.72\ J

Hence, The store energy is 2113109.72 J.

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Explanation:

3 0
3 years ago
A 75-g bullet is fired from a rifle having a barrel 0.540 m long. choose the origin to be at the location where the bullet begin
lyudmila [28]
Part a) The work done by the gas on the bullet is the integral of the force in dx, where x is the distance covered by the bullet inside the barrel with respect to the origin:
W= \int\limits^{0.540m}_{0} {F} \, dx =  \int\limits^{0.540m}_{0} {(16000+10000x-26000x^2)} \, dx =
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By substituting the length of the barrel, L=0.540 m, we find the total work done by the gas on the bullet:
W=16000(0.540m)+10000  \frac{(0.540m)^2}{2} - 26000  \frac{(0.540m)^3}{3}  =
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part b) The resolution of the problem is the same, we just have to use the new length of the barrel (L=0.95 m) inside the final formula, and we find the new value of the work:
W=16000(0.95m)+10000  \frac{(0.95m)^2}{2} - 26000  \frac{(0.95m)^3}{3}  =
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Answer:

Please find detailed explanation of second class levers below

Explanation:

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Examples of second class levers include; wheelbarrow, a bottle opener etc. In the bottle opener for example, the bottle lid (load) is in between the pivot of the opener and the hand opening it (effort).

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