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RUDIKE [14]
3 years ago
9

One way to store energy is in the rotational motion of a flywheel, and some have proposed using such technology to power automob

iles. one unit is based on a 6.5-\(\rm kg\) flywheel in the shape of a hoop of radius 0.11 \(\rm m\) that spins as fast as 70000 \(\rm rpm\).
Physics
1 answer:
miskamm [114]3 years ago
4 0

Answer:

The store energy is 2113109.72 J.

Explanation:

Given that,

Radius = 0.11 m

Mass = 6.5 kg

Spins = 70000 rpm

Suppose we need to find how much kinetic energy is stored by the flywheel when it is rotating at its maximum rate

We need to calculate the moment of inertia

Using formula of moment of inertia

I=mr^2

Put the value into the formula

I=6.5\times(0.11)^2

I=0.07865\ kg-m^2

We need to calculate the rotational kinetic energy

Using formula of rotational kinetic energy

K.E=\dfrac{1}{2}I\omega^2

Put the value into the formula

K.E=\dfrac{1}{2}\times0.07865\times(70000\times\dfrac{2\pi}{60})^2

K.E=2113109.72\ J

Hence, The store energy is 2113109.72 J.

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How much heat (in calories) are needed to raise the temperature of 60 g of water
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3 years ago
when a metal ball is heated through 30°c,it volume becomes 1.0018cm^3 if the linear expansivity of the material of the ball is 2
Vlad1618 [11]

Answer:

The original volume of the metal sphere is approximately 1 cm³

Explanation:

The given parameters are;

The temperature change of the metal ball, ΔT = 30°C = 30 K

The new volume of the metal ball, V₂  = 1.0018 cm³

The linear expansivity of the material ball, α = 2.0 × 10⁻⁵ K⁻¹

We have;

d₂ = d₁·(1 + α·ΔT)

Where;

d₁ = The original diameter of the metal ball

d₂ = The new diameter of the ball

From the volume of the ball, V₂, we have;

V₂ = 1.0018 cm³ = (4/3)×π×r₂³

Where;

r₂ = The new radius = d₂/2

∴ V₂ = 1.0018 cm³ = (4/3)×π×(d₂/2)³

∴ d₂ = ∛(2³ × 1.0018 cm³/((4/3) × π)) ≈ 1.241445 cm

d₁ = d₂/(1 + α·ΔT)

∴ d₁ ≈ 1.241445 cm/(1 + 2.0 × 10⁻⁵·K × 30 K) ≈ 1.24070058 cm

The original volume of the metal ball, V₁ = (4/3)×π×(d₁/2)³

∴ V₁ = (4/3)×π×(1.24070058/2)³ ≈ 0.99999902845 cm³ ≈ 1 cm³

The original volume of the metal sphere, V₁ ≈ 1 cm³.

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