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3 years ago

2. Calculate the molarity of a solution if there are 1.5 mol of NaCl in 2.3 L of solution.

Chemistry

1 answer:

rodikova [14]3 years ago

5 0

Answer:

0.65 M

Explanation:

Molarity (M) is the amount of moles of a substance per liter.

In other words, M = moles of substance / liters of solution

Since you're already given the moles of NaCl and the volume of the solution, you can plug those into the equation.

M = moles of NaCl / liters of solution

M = 1.5 mol NaCl / 2.3 L

M = 0.65 mol/L (or 0.65 M)

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Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility.

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The molar solubility is 7.4× $10^{-3}$ M and the solubility is 7.4× $10^{-3}$ g/L .

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The dissociation of silver bromide is given as ,

$AgBr$ → $Ag ^{+}$ + $Br^{-}$

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Since , one mole of $AgBr$ is dissociates and form one mole of each $Ag ^{+}$ and $Br^{-}$ ion . So, solubility is equal to molar solubility but unit is different.

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1 year ago

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Answer:

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3 years ago

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