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3 years ago

2. Calculate the molarity of a solution if there are 1.5 mol of NaCl in 2.3 L of solution.

Chemistry

1 answer:

rodikova [14]3 years ago

5 0

Answer:

0.65 M

Explanation:

Molarity (M) is the amount of moles of a substance per liter.

In other words, M = moles of substance / liters of solution

Since you're already given the moles of NaCl and the volume of the solution, you can plug those into the equation.

M = moles of NaCl / liters of solution

M = 1.5 mol NaCl / 2.3 L

M = 0.65 mol/L (or 0.65 M)

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Given that the concentration of myosin is 25pmol·L−1 and Rmax(Vmax)=208pmol·L−1·s−1 , determine the turnover number of the enzym

DedPeter [7]

Answer:

8.32 s⁻¹

Explanation:

Given that:

The concentration of myosin = 25 pmol/L

R_max = 208 pmol/L/s

The objective is to determine the turnover number of the enzyme molecule myosin, which has a single active site.

In a single active site of enzyme is known to be a region where there is binding of between substrate molecules, thereafter undergoing chemical reaction.

The turnover number of the enzyme is said to be the number of these substrate molecule which binds together are being converted into products.

The turnover number of the enzyme molecule of myosin can be calculated by the expression: $\dfrac{R_{max}}{concentration}$

⇒ $\dfrac{208 pmol/L/s}{25 pmol/L}$

= 8.32 s⁻¹

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3 years ago

Hydrogen is prepared commercially by the reaction of methane and water vapor at elevated temperatures. CH₄(????) + H₂O(????) ⇌ 3

sammy [17]

Answer:

6.2846

Explanation:

Given that:-

Concentrations at equilibrium :-

$[CH_4]=0.126\ M$

$[H_2O]= 0.242\ M$

$[CO]= 0.126\ M$

$[H_2]= 1.15\ M$

The equilibrium reaction is:-

$CH_4+H_2O\rightleftharpoons 3H_2+CO$

The expression for equilibrium constant is:

$K_{c}=\frac {\left [ H_2 \right ]^3\left [ CO \right ]}{\left [ CH_4 \right ]\left [ H_2O \right ]}$

Applying the values as:-

$K_c=\frac{1.15^3\times 0.126}{0.126\times 0.242}=6.2846$

<u>The equilibrium constant for the reaction is:- 6.2846</u>

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3 years ago

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Explanation:

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3 years ago

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Why will a toy train remain still if you push on the engine with

netineya [11]

Explanation:

Because when two equal forces are applied from opposite directions, they "eliminate" each other.

The train would go right if a 3N force was only applied in the right direction, and it would go left if the same force was only applied to the left.

If a 3N force was applied to the right and a 2N force to the left, it would equal a 1N force to the right (3-2=1).

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3 years ago