I choose question 1, so molarity is the concentration of a soulution expressed as the number of moles of solute by the litress of soulution. to get molarity you divide the moles of soulute by the litress of solution. soo 1 calculate the number of moles of solute present. 2 Calculate the number of litress solution present. 3. divide the number of moles of solute by the number of litress of solution
soo 1 mol of NaOH has a mass of 40.00 g, so moles of NaOH= 26.7. 1 mole divided 40.00 = 0.375. litress of solution = 650 g. im not sure why its a g i usally do it Ls so i guess its the way your teacher wants you to do it so do you know how to do that. so molarity = moles of solute and litress solution. sorry this probably didnt help i just wanted to add something that might help. im still working on this stuff myself hope this helps.
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(I hope this helps you!)
There are 41.1984 grams of silver in 2.3x 10^23 atoms of silver
Answer:
The molar mass of dry air = 28.94
Density = 1.29
Explanation:
Mm of N2= 28, Mm of O2= 32, Mm Ar= 39.9
78% of N2 by mole give = 0.78×28= 21.84
21% of O2 by mole give = 0.21× 32= 6.72
1% of At by mole give = 0.01× 39= 0.39
Hence overall molecular weight of air = 21.84+6.72+0.39= 28.94
Density = m/ v,
1- mole of air occupy 22.4dm^3 volume
Density= 28.94/22.4= 1.29
