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3 years ago

6

Jessica decides not to skip school because she does not want to lose her senior privileges if caught. Jessica is at what level o

f moral reasoning?
Pre-conventional
Conventional
Advanced
Post-conventional

1 answer:

Elena L [17]3 years ago

3 0

This one is also using pre-conventional moral reasoning.

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A water pump with a power of 3.4 × 102 watts lifts water at the rate of 7.5 × 10-2 meters/second from a water tank. What is the

Neporo4naja [7]

<h2>Hello!</h2>

The answer is:

The correct option is:

C. $4.5x10^{3}N$

<h2>Why?</h2>

To calculate the force exerted by the pump, we must remember the formula to calculate power, also, we must remember that power means work done in a determined period of time.

We have that power can be calculated by the following equation:

$Power(W)=F*V=N.\frac{m}{s}=\frac{N.m}{s}=1Watt$

So, we are given the following information:

$Power=3.4x10^{2}W=340W=340\frac{N.m}{s}\\\\V=\frac{7.5x^{-2}m }{s}=\frac{0.075m}{s}$

Now, substituting and calculating we have:

$Power(W)=F*V$

$340\frac{N.m}{s}=F*\frac{0.075m}{s}$

$F=\frac{340\frac{N.m}{s}}{\frac{0.075m}{s}}=4,533N=4.5x10^{3}N$

Hence, the correct option is:

C. $4.5x10^{3}N$

Have a nice day!

5 0

3 years ago

Object's velocity change

marshall27 [118]

the definition of acceleration in kinematics, allows to find that the correct answer is:

2. speed up ( acceleration)

The kinematics study the movement of the body, the acceleration is defined as the change of the speed by the time in the interval

a = Δv / t

Where the bold letters indicate vectors, a is the acceleration, v the velocity and t the time

Analyzing this expression we see that for there to be a change in velocity, there must be an acceleration of the body.

Let's analyze the different claims

1. True. If it is stopped and you start to move there is an acceleration, therefore there is a change in speed, but after you are moving the acceleration becomes zero and there is no change in speed

2. True. Whenever there is acceleration there is a change in speed

3. False. Moving slowly does not change the acceleration, therefore there is no change in speed

4. True. If you are moving and you stop at this moment there is an acceleration, therefore there is a change in speed, but after being stopped the acceleration is zero and there is no change in speed

5. False. If you change the direction at the instant of change there is an acceleration but after you go in the opposite direction there is not acceleration therefore there is no change in speed.

In conclusion using the definition of acceleration in kinematics, we can find the answer the condition for a change in velocity, the correct statement is:

2. speed up ( acceleration)

Learn more here: brainly.com/question/5063616

3 0

2 years ago

A 10 kg monkey climbs up a massless rope that runs over a frictionless tree limb and back down to a 15 kg package on the ground.

pshichka [43]

Answer:

A. 4,9 m/s2

B. 2,0 m/s2

C. 120 N

Explanation:

In the image, 1 is going to represent the monkey and 2 is going to be the package. Let a_mín be the minimum acceleration that the monkey should have in the upward direction, so the package is barely lifted. Apply Newton’s second law of motion:

$\sum F_y=m_1*a_m_i_n = T-m_1*g$

If the package is barely lifted, that means that T=m_2*g; then:

$\sum F_y =m_1*a_m_i_n=m_2*g-m_1*g$

Solving the equation for a_mín, we have:

$a_m_i_n=((m_2-m_1)/m_1)*g = ((15kg-10kg)/10kg)*9,8 m/s^2 =4,9 m/s^2$

Once the monkey stops its climb and holds onto the rope, we set the equation of Newton’s second law as it follows:

For the monkey: $\sum F_y = m_1*a \rightarrow T-m_1*g=m_1*a$

For the package: $\sum F_y = m_2*a \rightarrow m_2*g - T = m_2*a$

The acceleration a is the same for both monkey and package, but have opposite directions, this means that when the monkey accelerates upwards, the package does it downwards and vice versa. Therefore, the acceleration a on the equation for the package is negative; however, if we invert the signs on the sum of forces, it has the same effect. To be clearer:

For the package: $\sum F_y = -m_2*a \rightarrow T-m2*g=-m_2*a \rightarrow m_2*g -T=m_2 *a$

We have two unknowns and two equations, so we can proceed. We can match both tensions and have:

$m_1*a+m_1*g=m_2*g-m_2*a$

Solving a, we have

$(m_1+m_2)*a =(m_2 - m1)*g\\\\a=((m_2-m_1)/(m_1+m_2))*g \rightarrow a=((15kg-10kg)/(10kg+15kg))*9,8 m/s^2\\\\a= 2,0 m/s^2$

We can then replace this value of a in one for the sums of force and find the tension T:

$T = m_1*a+m_1*g \rightarrow T=m_1*(a+g)\\\\T = 10kg*(2,0 m/s^2+9,8 m/s^2) \\\\T = 120 N$

5 0

3 years ago

2. A car is moving with a constant speed of 10m/s. What is the total distance the car travels

Tems11 [23]

Answer:

1200 meters

Explanation:

there are 60 seconds in a minute times 2 is 120 ten times 120 is 1200

6 0

3 years ago

A car with a mass of 600 kg is traveling at a velocity of 10 m/s. How much kinetic energy does it have?

Viefleur [7K]

Answer:

KE = 30,000 J

Explanation:

KE = $\frac{1}{2}$ mv²

KE = $\frac{1}{2}$ (600)(10)²

KE = $\frac{1}{2}$ (600)(100)

KE = $\frac{1}{2}$ (60000)

KE = 30,000 J

5 0

3 years ago