Ask question

Ask question

All categories

3 years ago

6

Jessica decides not to skip school because she does not want to lose her senior privileges if caught. Jessica is at what level o

f moral reasoning?
Pre-conventional
Conventional
Advanced
Post-conventional

1 answer:

Elena L [17]3 years ago

3 0

This one is also using pre-conventional moral reasoning.

You might be interested in

You make a straight line when an object is

swat32

Answer:

can you explain more or..,.

Explanation:

8 0

3 years ago

Read 2 more answers

State Archimedes' principle.

vampirchik [111]

Answer:

Archimedes' principle states that, when a body is partially or completely immersed in a fluid, it experiences an apparent loss in weight that is equal to the weight of the fluid displaced by the immersed part of the body.

Explanation:

Archimedes' principle allows the buoyancy of an object partially or fully immersed in a fluid to be calculated. The downward force on the object is simply its weight. Thus, the net force on the object is the difference between the magnitudes

of the buoyant force and its weight. If this net force is positive, the object rises; if negative, the object sinks; and if zero, the object is neutrally buoyant - that is, it remains in place without either rising or sinking. In simple words,

8 0

3 years ago

Read 2 more answers

Convert to scientific notation:<br> 0.0035

Genrish500 [490]

3.5 x 10^-3 Should be it

3 0

3 years ago

A child\'s top is held in place, upright on a frictionless surface. The axle has a radius of r = 2.96 mm. Two strings are wrappe

sladkih [1.3K]

Answer:

Explanation:

Given

radius r=2.96 mm

Tension T=2.4 N

time taken=0.74 s

Let $\alpha$ be the angular acceleration

$2 T\times r=I\times \alpha$

$2\times 2.4\times 2.96\times 10^{-3}=0.5\times m\times (2.96\times 10^{-3})^2\times \alpha$

$\alpha =\frac{4\times 2.4}{m\times 2.96\times 10^{-3}}$

$\alpha =\frac{3.24\times 10^3}{m} rad/s^2$

$\omega =\omega _0+\alpha \cdot t$

$\omega =0+\frac{3.24\times 10^3}{m}\times 0.74$

$\omega =\frac{2.4\times 10^3}{m} rad/s$

Angular momentum

$L=I\omega$

$L=0.5\times mr^2\times \omega$

$L=0.5\times m\times (2.96\times 10^{-3})^2\times \frac{2.4\times 10^3}{m}$

$L=0.01051 kg-m^2/s$

4 0

3 years ago

A car is stopped at a traffic light. It then travels along a straight road so that its distance from the light is given by x(t)=

True [87]

Answer:

(a) average velocity = 17.6 m/s

(b) when t = 0, v = 0

when t = 4, v = 19.2 m/s

when t = 8, v = 28.8 m/s

(c) after starting from rest, the car will be at rest again in 20 s

Explanation:

Given;

x(t)=bt²−ct³, substitute the given values and the equation will become;

x(t)=3t²−0.1t³

(a)average velocity = total distance / total time

total distance, x(t) = 3t²−0.1t³

x(8) = 3t²−0.1t³

X(8) = 3(8)² - 0.1(8)³

X(8) = 140.8 m

total time = 8 s

average velocity = 140.8 / 8

average velocity = 17.6 m/s

(b) instantaneous velocity = dx / dt

dx / dt = 6t - 0.3t²

when t = 0

v = 0

when t = 4 s

v = 6(4) - 0.3(4²) = 19.2 m/s

when t = 8 s

v = 6(8) - 0.3(8²) = 28.8 m/s

(c) the velocity is zero at dx / dt = 0

6t - 0.3t² = 0

t(6 - 0.3t) = 0

t = 0 or 6 - 0.3t = 0

t = 0 or 0.3t = 6

t = 0 or t = 6 / 0.3

t= 0 or t = 20 s

After starting from rest, the car will be at rest again in 20 s

6 0

3 years ago