It takes a car 2 minute(s) to go from rest to 25 m/s east. What is the acceleration

Physics

1 answer:

yKpoI14uk [10]3 years ago

5 0

Explanation:

we first convert 2 minutes to seconds,which will give us 120s (2×60).

v=u +at where (v=final velocity,u is the initial velocity,a is the acceleration of the car and t the time taken)

V=25 m/s

u=0 m/s since the car started from rest 

t=120s

substituting the values we get 

25=0+a (120)

25=120a (diving both sides by 120 we get)

a=0.208m/s^2

You might be interested in

I need help on this science

Serga [27]

Ok ok ok ok ok ok ok ok ok

8 0

2 years ago

How to make a paper airplane curve down and fly upside down?

Ainat [17]

Throw it sideways and try to make it spin around but it needs to be thrown high up then it should kinda glide down

8 0

2 years ago

Read 2 more answers

How do I do this physics problem about potential energy and kinetic energy?

larisa86 [58]

Ok i apologise for the messy working but I'll try and explain my attempt at logic

Also note i ignore any air resistance for this.

First i wrote the two equations I'd most likely need for this situation, the kinetic energy equation and the potential energy equation.

Because the energy right at the top of the swing motion is equal to the energy right in the "bottom" of the swing's motion (due to conservation of energy), i made the kinetic energy equal to the potential energy as indicated by Ek = Ep.

I also noted the "initial" and "final" height of the swing with hi and hf respectively.

So initially looking at this i thought, what the heck, there's no mass. Then i figured that using the conservation of energy law i could take the mass value from the Ek equation and use it in the Ep equation. So what i did was take the Ek equation and rearranged it for m as you can hopefully see. Then i substituted the rearranged Ek equation into the Ep equation.

So then the equation reads something like Ep = (rearranged Ek equation for m) × g (which is -9.81) × change in height (hf - hi).

Then i simplify the equation a little. When i multiply both sides by v^2 i can clearly see that there is one E on each side (at that stage i don't need to clarify which type of energy it is because Ek = Ep so they're just the same anyway). So i just canceled them out and square rooted both sides.

The answer i got was that the max velocity would be 4.85m/s 3sf, assuming no losses (eg energy lost to friction).

I do hope I'm right and i suppose it's better than a blank piece of paper good luck my dude xx