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ZanzabumX [31]
3 years ago
14

It takes a car 2 minute(s) to go from rest to 25 m/s east. What is the acceleration

Physics
1 answer:
yKpoI14uk [10]3 years ago
5 0

Explanation:

we first convert 2 minutes to seconds,which will give us 120s (2×60).

<em>v</em><em>=</em><em>u</em><em> </em><em>+</em><em>at</em><em> </em><em>where</em><em> </em><em>(</em><em>v</em><em>=</em><em>final</em><em> </em><em>velocity</em><em>,</em><em>u</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>initial</em><em> </em><em>velocity</em><em>,</em><em>a</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>acceleration</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>car</em><em> </em><em>and</em><em> </em><em>t</em><em> </em><em>the</em><em> </em><em>time</em><em> </em><em>taken</em><em>)</em>

<em>V</em><em>=</em><em>25</em><em> </em><em>m</em><em>/</em><em>s</em>

<em>u</em><em>=</em><em>0</em><em> </em><em>m</em><em>/</em><em>s</em><em> </em><em>since</em><em> </em><em>the</em><em> </em><em>car</em><em> </em><em>started</em><em> </em><em>from</em><em> </em><em>rest</em><em> </em>

<em>t</em><em>=</em><em>120s</em>

<em>substituting</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>we</em><em> </em><em>get</em><em> </em>

<em>25</em><em>=</em><em>0</em><em>+</em><em>a</em><em> </em><em>(</em><em>120</em><em>)</em>

<em>25</em><em>=</em><em>120a</em><em> </em><em>(</em><em>diving</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>120</em><em> </em><em>we</em><em> </em><em>get</em><em>)</em>

<em>a</em><em>=</em><em>0.208m</em><em>/</em><em>s</em><em>^</em><em>2</em>

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Help with this question plz and show how you got it :) tysm!
spayn [35]
The hardest part of the job is to find the right formula to use, and write it down. You've already done that ! The rest is just turning the crank until an answer falls out.

You wrote. E = m g h.
Beautiful.
Now divide each side by (g h), and you'll have the formula for mass:

m = E / (g h).

You know all the numbers on the right side. Just pluggum in, do the arithmetic, and you'll have the mass.
5 0
3 years ago
A 950-kg car strikes a huge spring at a speed of 22m/s (fig. 11-54), compressing the spring 5.0m. (a) what is the spring stiffne
alukav5142 [94]

(a) The spring stiffness constant of the spring is 18,392 N/m.

(b) The time the car was in contact with the spring before it bounces off in the opposite direction is 0.23 s.

<h3>Kinetic energy of the car</h3>

The kinetic energy of the car is calculated as follows;

K.E = ¹/₂mv²

K.E = ¹/₂ x 950 x 22²

K.E = 229,900 J

<h3>Stiffness constant of the spring</h3>

The stiffness constant of the spring is calculated as follows;

K.E =  U = ¹/₂kx²

k = 2U/x²

k = (2 x 229,900)/(5)²

k = 18,392 N/m

<h3>Force exerted on the spring</h3>

F = kx

F = 18,392 x 5

F = 91,960 N

<h3>Time of impact</h3>

F = mv/t

t = mv/F

t = (950 x 22)/(91960)

t = 0.23 s

Learn more about spring constant here: brainly.com/question/1968517

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3 0
2 years ago
Use the information from the graph to answer the question.
galina1969 [7]

The displacement of the object as determined from the velocity-time graph is 562.5 m.

<h3>What is a velocity-time graph?</h3>

A velocity-time graph is a graph of the velocity of an object plotted in the vertical or y-axis of the graph against the time taken on the horizontal or x-axis.

The displacement of an object can be obtained from its velocity-time graph by calculating the total area under the graph.

The total area under the graph = area of triangle + area of rectangle

Area of triangle = b*h/2 =

Area of triangle = 25 * (35 - 10)/2 = 312.5 m

Area of rectangle = l * b

Area of rectangle = 10 * 25 = 250 m

Total area = (312.5 + 250) m

Total area = 562.5 m

Therefore, the displacement of the object is 562.5 m

In conclusion, the total area of a velocity-time graph gives the displacement.

Learn more about velocity-time graph at: brainly.com/question/28064297

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5 0
2 years ago
already did the work, i just need someone to see if i did the tangent line right? the line has to touch the point 0.6! thank you
Dmitrij [34]

The tangent looks good.

The curve is a bit crooked, at the 0.9 and 1.

But overall, cool graph.

5 0
3 years ago
A dog has a mass of 60kg and an acceleration of 2m/s/s. What is the force of the dog?
attashe74 [19]

Answer:

120 N

Explanation:

F=ma therefore 60kg times 2m/s^2 is 120 N

8 0
3 years ago
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