Answer: 80m
Explanation:
Distance of balloon to the ground is 3150m
Let the distance of Menin's pocket to the ground be x
Let the distance between Menin's pocket to the balloon be y
Hence, x=3150-y------1
Using the equation of motion,
V^2= U^s + 2gs--------2
U= initial speed is 0m/s
g is replaced with a since the acceleration is under gravity (g) and not straight line (a), hence g is taken as 10m/s
40m/s is contant since U (the coin is at rest is 0) hence V =40m/s
Slotting our values into equation 2
40^2= 0^2 + 2 * 10* (3150-y)
1600 = 0 + 63000 - 20y
1600 - 63000 = - 20y
-61400 = - 20y minus cancel out minus on both sides of the equation
61400 = 20y
Hence y = 61400/20
3070m
Hence, recall equation 1
x = 3150 - 3070
80m
I hope this solve the problem.
I think it might be D but I am not sure
The person is at rest with respect to the car. So the best answer is:
c. the front seat of the car.
Answer:
t = 36π seconds
Explanation:
For resolving this problem, we are going to consider a representative stadium of the United States. The Mercedes-Benz Stadium located in Atlanta, Georgia has an average radius of 90 m.
Then, its circumference measures:
L = 2πr
L = 2π(90)
L = 180π m
First, we estimate the wave's velocity: the average width of an person is 0.5 m, then the velocity is:
v = x/t
Where x: person's width
t: time
v = 0.5/0.1 = 5 m/s
The time required for the pulse to make one circuit around the stadium is:
t = x/v = 180π/5 = 36π seconds
Answer:

<h3>B. Speed at which it leaves the ground</h3>