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PilotLPTM [1.2K]

3 years ago

14

What happens when a book falls of a desk?

2 answers:

SVEN [57.7K]3 years ago

7 0

Answer:

is there a question to this to at you need help with?

MatroZZZ [7]3 years ago

5 0

Answer:

Happy Face excellent song

Explanation:

and gravity takes the book and pulls it to the ground

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If you traveled through space and landed on an unknown planet where gravity is 15 times as strong as the gravity on Earth, how m

viva [34]

First you would divide your weight on Earth by 9.8m/s which is the gravitational constant. This would give you your mass which would be 10.2 kg. To find the gravity of the unknown planet you would multiply 9.8m/s by 15 which would be 147m/s. Since weight is defined as mass times gravity you would substitute the mass you found earlier and multiply it by the new gravity. This would give you 10.2kg times 147 m/s which equals 1,499.4 lbs or 1,500 lbs if rounding.

8 0

3 years ago

What quaintly represents .500 mole at STP?

s2008m [1.1K]

.500 moles is roughly
.5 * 6.022 * 10^23 = 3.011*10^23 atoms. this is independent of STP
if it’s wrong i’m sorry

3 0

3 years ago

Read 2 more answers

why was it important to heat your hydrate gently for 5 minutes before heating it strongly for 10 minutes

snow_lady [41]

If the hydrate gets too hot it could start splattering and cause a loss of sample.

6 0

2 years ago

Be sure to answer all parts. Consider the reaction N2(g) + 3H2(g) → 2NH3(g)ΔH o rxn = −92.6 kJ/mol If 4.0 moles of N2 react with

Sphinxa [80]

Answer : The work done is, $1.98\times 10^4J$

Explanation :

The given balanced chemical reaction is:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

When 4 moles of $N_2$ react with 12 moles of $H_2$ then it gives 8 moles of $NH_3$

First we have to calculate the change in moles of gas.

Moles on reactant side = Moles of $N_2$ + Moles of $H_2$

Moles on reactant side = 4 + 12 = 16 moles

Moles on product side = Moles of $NH_3$

Moles on reactant side = 8 moles

Change in moles of gas = 16 - 8 = 8 moles

Now we have to calculate the change in volume of gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of gas = 1.0 atm

V = Volume of gas = ?

n = number of moles of gas = 8 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas = $25^oC=273+25=298K$

Putting values in above equation, we get:

$1.0atm\times V=8mole\times (0.0821L.atm/mol.K)\times 298K$

$V=195.7L$

As the number of moles of gas decreased. So, the volume also deceased. Thus, the volume of gas will be, -195.7 L

Now we have to calculate the work done.

Formula used :

$w=-p\Delta V$

where,

w = work done

p = pressure of the gas = 1.0 atm

$\Delta V$ = change in volume = -195.7 L

Now put all the given values in the above formula, we get:

$w=-p\Delta V$

$w=-(1.0atm)\times (-195.7L)$

$w=195.7L.artm=195.7\times 101.3J=19824.41J=1.98\times 10^4J$

conversion used : (1 L.atm = 101.3 J)

Thus, the work done is, $1.98\times 10^4J$

6 0

3 years ago

All of the following are true statements about catalysts except: Select one: a. A catalyst will speed the rate-determining step

liberstina [14]

<span>d. A catalyst will be used up in the reaction is wrong,
amount of catalyst should not change</span>

6 0

4 years ago