Answer:
Extensive or inextinsive and either physical or chemical
<h3>
<u>Answer</u> - 5.85g</h3>
<h3>
<u>Solution</u> - </h3>
Using the concentration equation, m = CVMo where m is the mass of solute, C is the concentration (M), V is the volume of solution (L) and Mo is molar mass of the solute (g):
Given,
Molar mass of NaCl, M = 58.5g/mol
Volume of the solution, V= 100ml = 0.1L
Molarity, S= 1M
Mass of the solute,W=?
W=SMV
= 1×58.5×0.1
= 5.85g
Answer:
See answer below
Explanation:
In this case, let's draw the butane molecule:
CH₃ - CH₂ - CH₂ - CH₃
According to what the exercise states, we removed an atom of hydrogen from the frist carbon. This could be any of the terminals. I'll grab the first from left to right.
CH₂⁺ - CH₂ - CH₂ - CH₃
When this happens, the atom of carbon is lacking one space and it forms a carbocation.
Followed this step, an hydroxile group replace the atom of hydrogen. The hydroxile is the OH, and when we have an alkane with an OH group in the molecule, we are actually converting this molecule into an alcohol, therefore the molecule formed is:
<h2>
OH - CH₂ - CH₂ - CH₂ - CH₃</h2><h2 />
Hope this helps
A)Mr.Greenjeans needs a control group for comparison.
hope this helps
