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Ahat [919]
2 years ago
9

50 points for 5 questions p.s if u get brainliest u get 50 moe and then u have 100 SO YAAAAAAY p.s dont answer the new one i for

got to add the points
1.What can federal appeals courts do?



Choose all answers that are correct.


Overturn the decisions of the district courts.


Remand cases back to lower courts.


Uphold the decisions of the lower courts.


Recommend cases be heard by the Supreme Court.
2.Why do the losing parties in civil trials and convicted criminals seek to involve the federal appeals courts in their cases?


because they feel that laws were incorrectly interpreted or applied in their cases


in order to force the winning side or the prosecution to present its evidence again


because they believe that their cases should be heard by magistrate judges


so that new appellate juries will hear the facts of their cases
3.How are federal judges selected?


Candidates are nominated and appointed by the Supreme Court unless the president uses the veto.


Candidates are nominated by Congress and voted upon by citizens over the age of 18 in federal elections.


Candidates are nominated by current federal judges and appointed by Congress if the House approves by a two-thirds majority vote.


Candidates are nominated and appointed by the president if the Senate approves by a majority vote.
4.What are two roles of magistrate judges?



Choose exactly two answers that are correct.


to hear preliminary evidence and decide if a case should be brought to trial


to appoint the U.S. attorney(s) for their districts


to issue court orders, such as search warrants


to deliver rulings on major cases involving federal law
5.What is the main duty of the United States Supreme Court?


to sentence or parole convicted criminals


to appoint judges to lower federal courts


to hear and rule on cases


to ratify or veto new laws thx UwU p.s dont answer the new one i for got to add the points
Physics
2 answers:
adelina 88 [10]2 years ago
8 0

Answer:

#1 = B, C, & D

#2 = A

#3 = C

#4 = C & A

#5 = C

Hope this helps! Have a good day :D!!

svetlana [45]2 years ago
4 0

Answer:

1. c

2. b

3. d

4. a&c

5. d

hope this helps

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Which of the following renaissance scientists made improvements to the telescope?
LenaWriter [7]
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7 0
3 years ago
How does Bohr’s model of the atom compare with Thomson’s model? They both describe atoms as small, indivisible spheres. They bot
Snowcat [4.5K]

Answer:

They both describe atoms as being made up of positive and negative matter.

Explanation:

In both Bohr's model and Thomson model, the atom consists of positively-charged matter and negatively-charged matter. However, the structure of the atom in the two models is totally different:

- in Thomson's model, the atom consists of a large sphere of uniform positive charge, and electrons (which are negatively charged) are scattered all around inside this sphere

- In Bohr's model, the atom consists of a small, positively charged nucleus, while the electrons (negatively charged) orbit around the nucleus in precise orbits.

7 0
3 years ago
Read 2 more answers
A mixture of gas expands from 0.03m³ to 0.06m³ at constant pressure of 1MPa & absorbs energy of 84 J. Calculate the change i
leonid [27]

Answer:54 kj

Explanation:P1 = P2 = 1000 kPa

1Q2 = 84 kJ

1W2 = P1 (V2 – V1)

= 1000 (0.06 – 0.03) = 30 kJ

1Q2 = 1W2 + 1U2

U2 – U1= 1Q2 – 1W2 = 84 – 30 = 54 kJ

4 0
2 years ago
A cylinder with a piston contains 0.300 mol of oxygen at 2.50×105 Pa and 360 K . The oxygen may be treated as an ideal gas. The
alukav5142 [94]

Answer:

a) W =  900   J.  b) Q =  3142.8   J . c) ΔU =  2242.8   J. d) W = 0. e) Q =   2244.78   J.  g) Δ U  =  0.

Explanation:

(a) Work done by the gas during the initial expansion:

The work done W for a thermodynamic constant pressure process is given as;

W  =  p Δ V

where  

p  is the pressure and  Δ V  is the change in volume.

Here, Given;

P 1 = i n i t i a l  p r e s s u r e  =  2.5 × 10^ 5   P a

T 1 = i n i t i a l   t e m p e r a t u r e  =  360   K

n = n u m b er   o f   m o l e s  =  0.300  m o l  

The ideal gas equation is given by  

P V = nRT

where ,

p  =  absolute pressure of the gas  

V =  volume of the gas  

n  =  number of moles of the gas  

R  =  universal gas constant  =  8.314   K J / m o l   K

T  =  absolute temperature of the gas  

Now we will Calculate the initial volume of the gas using the above equation as follows;

PV  =  n R T

2.5 × 10 ^5 × V 1  =  0.3 × 8.314 × 360

V1 = 897.91 / 250000

V 1  =  0.0036   m ^3  = 3.6×10^-3 m^3

We are also given that

V 2  =  2× V 1

V2 =  2 × 0.0036

V2 =  0.0072   m^3  

Thus, work done is calculated as;

W  =  p Δ V  = p×(V2 - V1)

W =  ( 2.5 × 10 ^5 ) ×( 0.0072  −  0.0036 )

W =  900   J.

(b) Heat added to the gas during the initial expansion:

For a diatomic gas,

C p  =  7 /2 ×R

Cp =  7 /2 × 8.314

Cp =  29.1  J / mo l K  

For a constant pressure process,  

T 2 /T 1  =  V 2 /V 1

T 2  =  V 2 /V 1 × T 1

T 2  =  2 × T 1  = 2×360

T 2  =  720  K

Heat added (Q) can be calculated as;  

Q  =  n C p Δ T  = nC×(T2 - T1)

Q =  0.3 × 29.1 × ( 720  −  360 )

Q =  3142.8   J .

(c) Internal-energy change of the gas during the initial expansion:

From first law of thermodynamics ;

Q  =  Δ U + W

where ,

Q is the heat added or extracted,

Δ U  is the change in internal energy,

W is the work done on or by the system.

Put the previously calculated values of Q and W in the above formula to calculate  Δ U  as;

Δ U  =  Q  −  W

ΔU =  3142.8  −  900

ΔU =  2242.8   J.

(d) The work done during the final cooling:

The final cooling is a constant volume or isochoric process. There is no change in volume and thus the work done is zero.

(e) Heat added during the final cooling:

The final process is a isochoric process and for this, the first law equation becomes ,

Q  =  Δ U  

The molar specific heat at constant volume is given as;

C v  =  5 /2 ×R

Cv =  5 /2 × 8.314

Cv =  20.785  J / m o l   K

The change in internal energy and thus the heat added can be calculated as;  

Q  = Δ U  =  n C v Δ T

Q =  0.3 × 20.785 × ( 720 - 360 )

Q =   2244.78   J.

(f) Internal-energy change during the final cooling:

Internal-energy change during the final cooling  is equal to the heat added during the final cooling Q  =  Δ U  .

(g) The internal-energy change during the isothermal compression:

For isothermal compression,

Δ U  =  n C v Δ T

As their is no change in temperature for isothermal compression,  

Δ T = 0 ,  then,

Δ U  =  0.

8 0
3 years ago
A glass of water with a mass of 0.35 kg rests on the edge of a desk 0.85 m
ivolga24 [154]

Answer:it’s c

Explanation:

Just is

3 0
3 years ago
Read 2 more answers
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