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vesna_86 [32]
4 years ago
12

_____________ forces are always attractive and the mass of an object determines how strong the ____________ pull is.

Physics
1 answer:
dolphi86 [110]4 years ago
6 0
Gravitational, gravitational ! both the option are same
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Please help me with this question...
Yakvenalex [24]
1) In first case, both the objects(hand & tea) are in direct contact, so heat will flow by the process of "Conduction" 

2) In this case, objects are not in direct contact, and heat is transferring from one to another by "Convection"

3) Here, there is no contact between the objects (our body & sun), sun light with heat comes through the process of "Radiation"

In short, Your Answers would be:
1) Conduction
2) Convection
3) Radiation

Hope this helps!
7 0
3 years ago
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The voltage in a circuit can be determined from the ____, total resistance, and capacitance
Dmitrij [34]
I think the answer is D, but I’m not at all sure :l
4 0
4 years ago
A bungee jumper who is about to jump has her energy stored entirely as
Morgarella [4.7K]

Answer:

it will get slower and eventually she will stop jumping because there isnt enough force on the gravity causing her to go up and down

Explanation:

!!

3 0
3 years ago
You can see stars brighter than magnitude +6 with your naked eye under dark sky conditions, and you can also see the full moon a
Mariana [72]
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6 0
3 years ago
The electric field 2.5 mm from a uniform sheet of charge is σ=800, NC. How much charge is contained in a 5.0x5.0 cm section of t
slamgirl [31]

Answer:

The charge is 2.75\times10^{-13}\ C

Explanation:

Given that,

Distance = 2.5 mm

Electric field = 800 NC

Length L=5.0\times5.0\times10^{-4}\ m

We need to calculate the linear charge density

Using formula of linear charge density

E=\dfrac{2k\lambda}{r}

\lambda=\dfrac{Er}{2k}

Put the value into the formula

\lambda=\dfrac{800\times2.5\times10^{-3}}{2\times9\times10^{9}}

\lambda=1.1\times10^{-10}\ C/m

We need to calculate the charge

Using formula of charge

Q=\lambda\timesL

Put the value into the formula

Q=1.1\times10^{-10}\times(5.0\times5.0\times10^{-4})

Q=2.75\times10^{-13}\ C

Hence, The charge is 2.75\times10^{-13}\ C

5 0
3 years ago
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