Answer:
4
Step-by-step explanation:
set
constrain:
Partial derivatives:
Lagrange multiplier:
![\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5Cend%7Barray%7D%5Cright%5D%3Da%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2x%5C%5C2y%5Cend%7Barray%7D%5Cright%5D%2Bb%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3x%5E2%5C%5C3y%5E2%5Cend%7Barray%7D%5Cright%5D)
4 equations:
By solving:
Second mathod:
Solve for x^2+y^2 = 7, x^3+y^3=10 first:
The maximum is 4
Answer:
10
Step-by-step explanation:
reduce the index of the radical and exponent with 2
|10|
The absolute value of any number is positive
10
Answer:
a
Step-by-step explanation:
Answer:
CI = 29.8 ± 3.53
Critical value is z = 2.58
Step-by-step explanation:
First of all let's find margin of error. It is given by the formula;
ME = zσ/√n
We are given;
Standard deviation; σ = 3.62
Sample size; n = 7
Mean; x¯ = 29.8
Now, z-value for 99% Confidence level is 2.58
Thus;
ME = (2.58 × 3.62)/√7
ME = 3.53
CI is written as;
CI = x¯ ± ME
CI = 29.8 ± 3.53
Critical value is z = 2.58
3(x + 2) > x
3x + 6 > x
3x - 3x + 6 > x - 3x
6 > -2x
6/-2 < -2x/-2
-3< x
(When dividing by a negative, reverse the direction of the inequality side, reverse it EVERY time you divide by a negative)
ANSWER: -3 < x
