862^-10 my friend this is the answer
Depression in freezing point (Δ

) =

×m×i,
where,

= cryoscopic constant =

,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For

)
Thus, (Δ

) = 1.86 X 0.0085 X 2 =

Now, (Δ

) =

- T
Here, T = freezing point of solution

= freezing point of solvent =

Thus, T =

- (Δ

) = -
Answer:
approximately 15.1 grams.
Explanation:
The key to chemistry is to change everything to moles. Then when you have the answer in moles change the answer back to grams, liters, or whatever you want.
change 25 grams of potassium chlorate to moles.
calculate the gram molecular mass of potassium chlorate.
Chlorate is Cl with 3 oxygens. ate = saturated. Chlorine has seven valance electrons when it is saturated six of these electrons are used by oxygen ( 2 electrons per oxygen) leaving only 1 electron.
1 K x 39 grams/mole
+1 Cl x 35.4 grams/ mole
+3 O x 16 grams/ mole
= 122.4 grams / mole Potassium Chlorate
25
122.4
= moles.
2.05 moles of Potassium Chlorate.
There is a 1:1 mole ratio. 1 mole of Potassium Chlorate will produce 1 mole of Potassium Chloride.
2.05 moles of Potassium Chlorate will produce 2.05 moles of Potassium Chloride.
Find the gram molecular mass of Potassium Chloride.
1 K x 39 = 39
+1 Cl x 35.4 = 35.4
= 74.4 grams / mole.
2.05 moles x 74.4 grams/ mole = 15.2 grams
Hope it helps :)
Answer:
Only changes in temperature will influence the equilibrium constant
. The system will shift in response to certain external shocks. At the new equilibrium
will still be equal to
, but the final concentrations will be different.
The question is asking for sources of the shocks that will influence the value of
. For most reversible reactions:
- External changes in the relative concentration of the products and reactants.
For some reversible reactions that involve gases:
- Changes in pressure due to volume changes.
Catalysts do not influence the value of
. See explanation.
Explanation:
.
Similar to the rate constant, the equilibrium constant
depends only on:
the standard Gibbs energy change of the reaction, and
the absolute temperature (in degrees Kelvins.)
The reversible reaction is in a dynamic equilibrium when the rate of the forward reaction is equal to the rate of the backward reaction. Reactants are constantly converted to products; products are constantly converted back to reactants. However, at equilibrium
the two processes balance each other. The concentration of each species will stay the same.
Factors that alter the rate of one reaction more than the other will disrupt the equilibrium. These factors shall change the rate of successful collisions and hence the reaction rate.
- Changes in concentration influence the number of particles per unit space.
- Changes in temperature influence both the rate of collision and the percentage of particles with sufficient energy of reaction.
For reactions that involve gases,
- Changing the volume of the container will change the concentration of gases and change the reaction rate.
However, there are cases where the number of gases particles on the reactant side and the product side are equal. Rates of the forward and backward reaction will change by the same extent. In such cases, there will not be a change in the final concentrations. Similarly, catalysts change the two rates by the same extent and will not change the final concentrations. Adding noble gases will also change the pressure. However, concentrations stay the same and the equilibrium position will not change.
Answer:
oceanic formation is the right answer.
Explanation:
this os becoz they slide a past each other and do not rub against each other