Because they follow the octet rule and the outer most electrons, the valence electron shell is full.
Answer:
1. CBr4
2. C5H12
3. CF4
4. C8H17NH2
Explanation:
1. The boiling point of a molecule depends on its structure. Because the boiling point of molecules of similar size, depends on the differences in functional groups of the molecule.
For example CBr4 have a higher boiling point than other compounds because they have both London dispersion forces and dipole-dipole interactions.
2. Non-polar molecules like C5H12 will have low melting and boiling points, because they are held together by the weak van der Waals forces.
Answer: 31.55 g
Explanation:
- The mass number of Fluoride atom (F) = 18.99 g/mol, so mass number of fluorine gas (F2) = 37.98 g/mol.
- 1 mole of (F2) [which has 37.98 g/mol] contains Avogadro’s number of molecules (6.02×10^23 molecules),
so 1 mole of (F2) with 37.98 g/mol → 6.02×10^23 molecules.
- Using cross multiplication,
37.98 g/mol of (F2) → 6.02 ×10^23 molecules
? → 5.00 ×10^23 molecules
Hence the mass of 5.00×10^23 molecules of F2 = (37.98 × 5.00 × 10^23) / 6.02 ×10^23 = 31.55 g..
The kinetic theory<span> describes a </span>gas<span> as a large number of submicroscopic </span>particles<span>(atoms or </span>molecules<span>), all of which are in constant rapid motion that has randomness arising from their many </span>collisions<span> with each other and with the walls of the container.</span>
Answer:
a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O
b. The conversion factor that Jacob did, was wrong.
Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:
9.45 mol . 102 g / 1 mol = 963.9 g
Explanation:
Al₂O₃ → Aluminum oxide
We determine the molar mass:
Molar mass Al . 2 + Molar mass O . 3
27 g/mol . 2 + 16 g/mol . 3 = 102 g/mol
a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O
b. The conversion factor that Jacob did, was wrong.
Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:
9.45 mol . 102 g / 1 mol = 963.9 g
