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3 years ago

10

Describe the motion of the blocks before and after they are knocked down. Also describe the interactions of

1 answer:

vodka [1.7K]3 years ago

8 0

Potential energy I think that’s what your talking about after when it gets hit that potential turns into kinetic

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I feel dvmb for asking this question but... help? Please?

VMariaS [17]

<u>Force</u>, it can speed up or slow down an object which can change the direction in which an object is moving.

8 0

3 years ago

A disk initially rotated counterclockwise at 1.0 rad/s, but has a counterclockwise angular acceleration of 0.50 rad/s^2 for 2 se

Mumz [18]

Answer:

Initial angular position of the disc is 3 radian

Explanation:

As we know that the angular acceleration of the disc is given as

$\alpha = 0.50 rad/s^2$

initial angular speed is given as

$\omega = 1 rad/s$

now we know that angular displacement of the disc is given as

$\theta = \omega t + \frac{1}{2}\alpha t^2$

$\theta = 1(2) + \frac{1}{2}(0.5)(2^2)$

$\theta = 3 rad$

now we have

$\theta_f - \theta_i = 3 rad$

$6 rad - \theta_i = 3$

$\theta_i = 3 ard$

8 0

3 years ago

Water is flowing into a factory in a horizontal pipe with a radius of 0.0183 m at ground level. This pipe is then connected to a

timama [110]

Answer:

$0.0168 m^3/s$

Explanation:

We are given that

$r_1=0.0183 m$

$h_1=0$

$r_2=0.0420 m$

$h_2=12.6 m$

Let $P_1=P_2=P$

By using Bernoulli theorem

$P+\frac{1}{2}\rho v^2_1+\rho gh_1=P+\frac{1}{2}\rho v^2_2+\rho gh_2$

$\frac{1}{2}\rho v^2_1+\rho gh_1=\frac{1}{2}\rho v^2_2+\rho gh_2$

$v^2_1+2gh_1=v^2_2+2gh_2$

$A_1v_1=A_2v_2$

$v_1=\frac{A_2v_2}{A_1}$

$(\frac{A_2}{A_1})^2v^2_2+2g\times 0=v^2_2+2\times 9.8\times 12.6$

$(\frac{\pi r^2_2}{\pi r^2_1})^2v^2_2-v^2_2=246.96$

$v^2_2((\frac{r^2_2}{r^2_1})^2-1)=246.96$

$v^2_2=246.96\frac{r^4_1}{r^2_4-r^4_1}$

$v_2=\sqrt{246.96\frac{r^4_1}{r^4_2-r^4_1}}$

$v_2=\sqrt{246.96\times \frac{(0.0183)^4}{(0.042)^4-(0.0183)^4}}$

$v_2=3.038 m/s$

Volume flow rate = $A_2v_2$

Volume flow rate = $\pi r^2_2v_2=\pi (0.042)^2\times 3.038=0.0168 m^3/s$

3 0

3 years ago

What are the very small participes that make up all matter

Semenov [28]

<u>Answer</u> :

atom

<u>E</u><u>xplaination</u> :

You cannot see the fundamental particles that makes up matter.

Yet, ll matter os composed of such particle called atoms.

atoms - the smallest particle of an element that retains its identity in a chemical reaction.

<em>pls mark as brainliest...</em>

6 0

4 years ago

The driver of a car wishes to pass a truck that is traveling at a constant speed of 19.3 m/s . Initially, the car is also travel

miss Akunina [59]

Answer:

A) t = 10.56 s, B) x = 235 m, C) v = 25.2 m / s

Explanation:

A) We can solve this problem using kinematics expressions.

The distance traveled by the truck is

x_c = v_c t

Distance traveled by the car.

The car must travel the distance that separates them from the truck x₀=25.0. Return to the lane at x₁ = 26.5 m. the length of the truck x₂=20.7m and the length of the car x₃ = 2 4.5 = 9 m, therefore the total length traveled by the car is

x_t = x₁ + x₂ + x₃

x_t = 26.5 + 20.7 +9 = 56.2 m

the distance traveled by the car when it returns to the lane is

x_c + x_t = x₀ + v₀ t + ½ a t²

when the car passes the car the distance traveled by the two vehicles is the same, we substitute

v_c t + x_t = x₀ + v₀ t + ½ a t²

½ a t² + t (v₀ -v_c) + (x₀ - x_t) = 0

we substitute the values

½ 0.560 t² + t (19.3 -19.3) + (25.0 - 56.2) =

0.28 t² -31.2 = 0

t = $\sqrt{ \frac{31.2}{0.28} }$

t = 10.56 s

This is the time it takes for the car to pass the truck and back into the lane.

B) the distance traveled is

x = v₀ t + ½ a t²

x = 19.3 10.56 + ½ 0.560 10.56²

x = 235 m

C) the final velocity is

v = v₀ + a t

v = 19.3 + 0.560 10.56

v = 25.2 m / s

3 0

3 years ago