Explanation:
It is given that,
Charge, 
Radius of the disk, R = 1.25 cm = 0.0125 m
(a) Electric field at a distance of 2 cm from the center of the disk. It can be calculated using the formula as :
![E=\dfrac{\sigma}{2\epsilon_o}[1-\dfrac{x}{\sqrt{x^2+R^2}}]](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B%5Csigma%7D%7B2%5Cepsilon_o%7D%5B1-%5Cdfrac%7Bx%7D%7B%5Csqrt%7Bx%5E2%2BR%5E2%7D%7D%5D)
Where
is the surface charged density, 
So, ![E=\dfrac{1.32\times 10^{-5}}{2\times 8.85\times 10^{-12}}[1-\dfrac{0.02}{\sqrt{0.02^2+0.0125^2}}]](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B1.32%5Ctimes%2010%5E%7B-5%7D%7D%7B2%5Ctimes%208.85%5Ctimes%2010%5E%7B-12%7D%7D%5B1-%5Cdfrac%7B0.02%7D%7B%5Csqrt%7B0.02%5E2%2B0.0125%5E2%7D%7D%5D)
The direction of electric field is outwards.
(b) Suppose that the charge were all pushed away from the center and distributed uniformly on the outer rim of the disk. So, the electric field due to the ring is :
The direction of electric field is outwards.
(c) If the charge is all brought to the center of the disk, The electric field at the center of disk is given by :
(d) he field in part (a) stronger than the field in part (b). This is due to the reason that the charge at the center of the ring is 0.
(e) The field in part (c) the strongest of the three fields because the for a point charge the charges are at same distances.
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FORMULA:
ANSWER:
We are given with mass of car 394kg and velocity of car 15m/s.
Plugging the respective value,
- K.E. = 1/2 × 394 × 15²
- K.E. = 197 × 225
- K.E. = 44,325J
8. epiglottis
9. trachea
10. lugs
11.diaphragm
Answer: A wavelength is how long ONE wave is. First divide the distance of the whole diagram by the number of waves. you will get 2m. This is the answer.
