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Blababa [14]
2 years ago
8

I need help with these please. I’m using 19 points for this.

Chemistry
1 answer:
Rainbow [258]2 years ago
4 0

11. Convection

12.A=Convectionn

B=Radiation

C=Conduction

15=A

Sorry, thatis the most i can do

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I need help doing this please. It’s an image
Ne4ueva [31]

Answer:

k+

Ba2+

Al3+

K+

S2-

you may think that if it has a + it would be bigger, but it is actually the opposite.

5 0
3 years ago
What are the three different types of selective breeding
balandron [24]

first of all there is only two types of selective breeding and they are hybridization and inbreeding.

3 0
3 years ago
If one adds 0.1 mol of the weak acid hf (pk_a = 3.2) to a solution with a ph = 2, which species would be most abundant and how m
zavuch27 [327]

F^{-} is most abundant and 6310 times more than HF.

<h3>What is a strong and weak acid?</h3>

When an acid is dissolved in water, all of its molecules disintegrate, making the acid powerful.

When an acid is dissolved in water, only a small number of its molecules disintegrate, making the acid weak. Strong acids have a lower pH than weak acids.

The powerful acids include perchloric acid, chloric acid, nitric acid, sulfuric acid, hydrobromic acid, and hydroiodic acid.

Given:

Pka=3..2

pH=7

Let the volume be 1 liter

[HF]=01 M

pH=pka+log \frac{F^{-}}{HF} \\\\7=3.2+log\frac{F^{-}}{HF} \\3.8=log\frac{F^{-}}{HF}\\ \frac{F^{-}}{0.1}=10^{3.8} \\F^{-}=630.95 M

Now,

\frac{F^{-}}{HF}=\frac{630.95}{0.1}\\ =6309.57

F-:HF= 6309.57:1

Therefore, the most abundant is F^{-}and has 6310 times more than HF is F^{-}.

To know more about strong and weak acids, visit: brainly.com/question/12811944

#SPJ4

4 0
1 year ago
A sample of gas at a pressure of 121.59 kPa, a volume of 31 L, and a temperature of 360 K contains how many moles of gas? A. 0.7
natali 33 [55]

Answer:

C. 1.3 mol

Explanation:

PV = nRT

where P is absolute pressure,

V is volume,

n is number of moles,

R is universal gas constant,

and T is absolute temperature.

Given:

P = 121.59 kPa

V = 31 L

T = 360 K

R = 8.3145 L kPa / mol / K

Find: n

n = PV / (RT)

n = (121.59 kPa × 31 L) / (8.3145 L kPa / mol / K × 360 K)

n = (3769.29 L kPa) / (2993.22 L kPa / mol)

n = 1.26 mol

Round to two significant figures, there are 1.3 moles of gas.

4 0
3 years ago
Newtons first law second law and third law <br><br> help
Romashka [77]

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation:

hope this helps

7 0
3 years ago
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