Answer:
V₂ = 568.9 mL
Explanation:
Given data:
Volume of gas = 550 mL
Pressure of a gas = 960 mmHg
Temperature = 200.0°C ( 200+273 = 473 K)
Final volume = ?
Final pressure = 830 mmHg
Final temperature = 150°C (150+273 = 423 K)
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 960 mmHg × 550 mL × 423 K / 473 K ×830 mmHg
V₂ = 223344000 mL / 392590
V₂ = 568.9 mL
Answer:
Write a balanced chemical reaction:
N2 + 3H2 ==> 2NH3
Looking at the mole ratios in this balanced equation you can see it takes 3 moles H2 to make 2 moles NH3. So, next calculate the moles of NH3 represented by 1.80 g and then convert to moles of H2 needed:
moles of NH3 = 1.80 g x 1 mole/17 g = 0.106 moles NH3
Moles H2 needed = 0.106 moles NH3 x 3 moles H2/2 moles NH3 = 0.159 moles H2 needed
Grams H2 needed = 0.159 moles x 2 g/mole = 0.318 grams H2 needed
Explanation:
Assuming all other conditions equal, then, yes, the density would not change regardless of the mass of the substance. This is because the density is a ratio of the mass substance to its volume. If you increase the mass, the volume displaced would also be greater. So, it would just adjust making the density constant. This is applicable if it is at the same temperature and pressure conditions.
