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mote1985 [20]
3 years ago
12

Balance the foll. equations

Chemistry
2 answers:
s2008m [1.1K]3 years ago
8 0

Answer:

naf+so2+nho3

Explanation:

beacause sodium is main solution in this equation

spin [16.1K]3 years ago
7 0

Answer:

e) P + O2 → P2O5

balanced equation

4P + 5O2 → 2P2O5

f) NaCl + F2 → NaF + Cl2

balanced equation

2NaCl + F2 → 2NaF + Cl2

g) K + MgBr2 → KBr + Mg

balanced equation

2K +MgBr2 → 2KBr +Mg

h) Mg + O2 → MgO

balanced equation

2Mg + O2 → 2MgO

i) Al + O2 → Al2O3

balanced equation

4Al + 3O2 → 2Al2O3

hope this helps you!

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2. The air pressure inside a submarine is 0.56 atm. What would be the pressure in<br> mmHg?
Soloha48 [4]
The answer would be 425.599 because 1 ATM is 760 mmHg.
8 0
3 years ago
Is carbon monoxide an element a compound a heterogeneous mixture or a homogeneous mixture?
Scrat [10]
Answer:  Carbon monoxide, or "CO", is a compound.  This is a homogeneous compound (not a mixture).
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3 0
3 years ago
At 338 mm hg and 72 c a sample of carbon monoxide gas occupies a volune of 0.225 L the gas transferred to a 1.50 L flask and the
Elis [28]

Answer:

P₂  = 0.09 atm

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 0.225 L

Initial pressure = 338 mmHg (338/760 =0.445 atm)

Initial temperature = 72 °C (72 +273 = 345 K)

Final temperature = -15°C (-15+273 = 258 K)

Final volume = 1.50 L

Final pressure = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

P₂ = P₁V₁ T₂/ T₁ V₂ 

P₂ = 0.445 atm × 0.225 L × 258 K / 345 K × 1.50 L

P₂  =  25.83 atm .L.  K  / 293 K . L

P₂  = 0.09 atm

7 0
4 years ago
How to economically produce fine greens
nika2105 [10]

Answer:

A transition to renewable energy and to replace fossil fuels would take care of economically producing fine greens. Also, a transition to energy conservation and efficient energy use would help in this process.

Have a great day!

5 0
3 years ago
According to Hund's rule of maximum spin multiplicity, how many singly-occupied orbitals are there in the valence shells of the
leva [86]

Answer:

A) carbon  - 2

B) cobalt  - 3

C) sulfur   - 2

D) fluorine   - 1

E) titanium   - 2

F) germanium  - 2

Explanation:

Hund's rule of maximum multiplicity:-

Firstly, every orbital which is present in the sublevel is singly occupied and then the orbital is doubly occupied.  

(A) Carbon.

The electronic configuration is -  

1s^22s^22p^2

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, Carbon has 2 singly occupied orbitals.

(B) Cobalt.

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{7}4s^2

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 4 electrons will be paired in 2 orbitals and 3 orbitals will be singly filled in cobalt.

(C) Sulfur.

The electronic configuration is -  

1s^22s^22p^63s^23p^4

Thus, 3s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 2 electrons will be paired in 1 orbital and 2 orbitals will be singly filled in sulfur.

D) fluorine

The electronic configuration is -  

1s^22s^22p^5

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 4 electrons will be paired in 2 orbitals and 1 orbital will be singly filled in fluorine.

E) Titanium

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{2}4s^2

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 2 orbitals will be singly filled in titanium.

F) Germanium

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{10}4s^24p^2

Thus, 4s, 3d orbitals are fully filled and p orbital can singly filled 3 electrons. Thus, Germanium has 2 singly occupied orbitals.

4 0
3 years ago
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