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3 years ago

Balance the foll. equations

Chemistry

2 answers:

s2008m [1.1K]3 years ago

8 0

Answer:

naf+so2+nho3

Explanation:

beacause sodium is main solution in this equation

spin [16.1K]3 years ago

7 0

Answer:

e) P + O2 → P2O5

balanced equation

4P + 5O2 → 2P2O5

f) NaCl + F2 → NaF + Cl2

balanced equation

2NaCl + F2 → 2NaF + Cl2

g) K + MgBr2 → KBr + Mg

balanced equation

2K +MgBr2 → 2KBr +Mg

h) Mg + O2 → MgO

balanced equation

2Mg + O2 → 2MgO

i) Al + O2 → Al2O3

balanced equation

4Al + 3O2 → 2Al2O3

hope this helps you!

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A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°C. What is the magnitude of k at 95.0°C if Ea =

never [62]

Answer:

k ≈ 9,56x10³ s⁻¹

Explanation:

It is possible to solve this question using Arrhenius formula:

$ln\frac{k2}{k1} = \frac{-Ea}{R} (\frac{1}{T2} -\frac{1}{T1} )$

Where:

k1: 1,35x10² s⁻¹

T1: 25,0°C + 273,15 = 298,15K

Ea = 55,5 kJ/mol

R = 8,314472x10⁻³ kJ/molK

k2 : ???

T2: 95,0°C+ 273,15K = 368,15K

Solving:

$ln\frac{k2}{k1} = 4,257$

$\frac{k2}{k1} = 70,593$

${k2} = 9,53x10^3 s^{-1}$

I hope it helps!

5 0

3 years ago

2. 27.8 mL of an unknown were added to a 50.0-mL flask that weighs 464.7 g. The total mass of the flask and the liquid is 552.4

agasfer [191]

Answer:

$d=4.24x10^{-4}\frac{lb}{in^3}$

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

$d=\frac{m}{V}$

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

$m=552.4g-464.7g=87.7g$

So that we are now able to calculate the density in g/mL first:

$d=\frac{87.7g}{27.8mL}=3.15g/mL$

Now, we proceed to the conversion to lb/in³ by using the following setup:

$d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}$

Regards!

6 0

3 years ago