The value of X for this chemical reaction is 1.65 x 10⁻⁴
<u>Explanation:</u>
Mg (OH)₂(s) <==> Mg²⁺+(aq) + 2OH₋₁(aq)
Kc= 1.80x10⁻¹¹
KC = [Mg²⁺][OH-]²
Let us assume
Put X = [Mg²⁺] and 2x =
[OH-]
1.80x10-11 = (X) (2X)²
1.80x10-11 = 4X³
X³ = 4.5x10⁻¹²
On simplifying the equation we get,
X = 1.65 x 10⁻⁴
The value of X for this chemical reaction is 1.65 x 10⁻⁴
A chemical reaction between the metals and the electrolyte frees more electrons in one metal than it does in the other. The metal that frees more electrons develops a positive charge, and the other metal develops a negative charge.
Answer:
σ*2pₓ, also called 
Explanation:
I have drawn the MO diagram for fluorine below.
Each F atom contributes seven valence electrons, so we fill the MOs of fluorine with 14 electrons.
We have filled the 
and 
MOs.
They are the highest occupied molecular orbitals (HOMOs).
The next unfilled level (the LUMO) is the σ*2pₓ orbital. If you use the symmetry notation, it is called the orbital.
This is the orbital that fluorine uses when it acts as an electron acceptor.
4 moles of water will have 4 number of water molecules
Answer is: there is 3,36 micrograms of iron in <span>sample of Greg's blood.
</span>m(Fe) = 42 mcg(micrograms).
V(Fe) = 1 dL = 1 dL · 100 mL/1dL.
V(Fe) = 100 mL.
Make proportion: m(Fe) : 8 mL = 42 mcg : 100 mL.
100 mL · m(Fe) = 8 mL · 42 mcg.
m(Fe) = 336 mL·mcg ÷ 100 mL.
m(Fe) = 3,36 mcg.
