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Ainat [17]
4 years ago
15

The physical The physical process of evaporation involves -process of evaporation involves...

Chemistry
1 answer:
kotykmax [81]4 years ago
7 0
The absortion of energy to separate the molecules. In the liquid state the molecules are closer and to manage the separation neededd in the gas state the molecules need energy from the surroundings.
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Boiling is an example of a physical property. How do the particles of gas compare to the particles as a liquid?
Stolb23 [73]
Particles of gas are more scarcely placed  as compared to that of liquid.

the intermolecular forces will be less in gaseous state and hence is less stable
7 0
3 years ago
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A series of chemical reactions in the mitochondria that converts glucose, fatty acids, or glycerol into carbon dioxide, NADH, an
Lemur [1.5K]

The Krebs cycle is the correct answer.

6 0
3 years ago
Can someone give a brief description of
sesenic [268]

Answer:

1) Dispersion forces: It is a type of force which is present between atoms and molecules. It is a weakest intermolecular force that occurs between atoms. It is also called induced dipole-induced dipole attraction.

2. Dipole-dipole: It is a type of attractive force which is present between the negative end of one molecule with the positive end of another molecule. This type of attractive force occurs between polar molecules.

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4 0
3 years ago
How many moles FeBr3 are required<br> to generate 275 g NaBr?<br><br> 2FeBr3 + 3Na₂S → Fe₂S3 +6NaBr
slega [8]

Answer:

0.893mol

Explanation:

n = m ÷ M

= 275 ÷ (23 + 80)

= 2.67 mol

* now use the Mol ratio *

NaBr : FeBr3

6 : 2

2.67 : x

5.67 = 6x

n( FeBr3 ) = 0.893 mol

8 0
2 years ago
The radioactivity due to carbon-14 measured in a piece of a wood from an ancient site was found to produce 20 counts per minute
ss7ja [257]

Answer:

The answer is "17200 years".

Explanation:

Given:

A = 20 \ \frac{counts}{minute}\\\\A_{o} = 160\ \frac{counts}{minute}

Let the half-life of carbon-14, is beta emitter, is T = 5730\ years

Constant decay \ w = \frac{0.693}{ T}

= 1.209 \times 10^{-4} \ \frac{1}{year}\\

The artifact age t= ?

A = A_{o} e^{-wt} \\\\e^{-wt} = \frac{A}{A_{o}}\\\\-wt = \ln \frac{A}{A_{o}}\\\\= -2.079\\\\t = 1.7199 \times 10^{4} \ years\\\\\sim \ 17200\  years\\

5 0
3 years ago
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