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2 years ago

Which practice is an unsustainable way of managing resources? Please help

Physics

1 answer:

oee [108]2 years ago

3 0

Answer:

I would say it is recycling nonrenewable minerals instead of throwing them away.

Explanation:

using grocery bags only once before disposing them is also bad, but plastic is not really a resource compared to how minerals are resources.

if we recycle nonrenewable resources instead of throwing them away we would damage true resources.

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Which form of heat transfer occurs when objects of two temperatures touch

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Conducting because it occurs when two objects touch and heat is transferred

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3 years ago

What force is the total force felt by an object?

skelet666 [1.2K]

Answer:

net force

Explanation:

Net force felt by an object.

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2 years ago

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2 years ago

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You have been called in by your neighborhood safety council to advise them about installing a barrier on a dangerous curve that

Alborosie

Answer: The softer barrier is the better option

Explanation:

1) When is a car is moving at a certain speed, it has a certain amount of momentum (p=mv). A collision against a barrier would cause its momentum to decrease to 0. A change in momentum is Impulse

2) The formula for Impulse: J = f * Δt

J is Impulse

f is the force applied during the time Δt

A tough barrier would produce a smaller Δt, which means more force is applied on the car. (J is always constant)

A softer barrier would apply less force on the car, which means Δt is large.

Answer: The softer barrier is the better option

4 0

2 years ago

A 0.600 kg block is attached to a spring with spring constant 15 N/m. While the block is sitting at rest, a student hits it with

gulaghasi [49]

Answer:

8.8 cm

31.422 cm/s

Explanation:

m = Mass of block = 0.6 kg

k = Spring constant = 15 N/m

x = Compression of spring

v = Velocity of block

A = Amplitude

As the energy of the system is conserved we have

$\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{0.6\times 0.44^2}{15}}\\\Rightarrow A=0.088\ m\\\Rightarrow A=8.8\ cm$

Amplitude of the oscillations is 8.8 cm

At x = 0.7 A

Again, as the energy of the system is conserved we have

$\dfrac{1}{2}kA^2=\dfrac{1}{2}mv^2+\dfrac{1}{2}kx^2\\\Rightarrow v=\sqrt{\dfrac{k(A^2-x^2)}{m}}\\\Rightarrow v=\sqrt{\dfrac{15(0.088^2-(0.7\times 0.088)^2)}{0.6}}\\\Rightarrow v=0.31422\ m/s$

The block's speed is 31.422 cm/s

4 0

2 years ago