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3 years ago

Which practice is an unsustainable way of managing resources? Please help

Physics

1 answer:

oee [108]3 years ago

3 0

Answer:

I would say it is recycling nonrenewable minerals instead of throwing them away.

Explanation:

using grocery bags only once before disposing them is also bad, but plastic is not really a resource compared to how minerals are resources.

if we recycle nonrenewable resources instead of throwing them away we would damage true resources.

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You drive in a straight line at 24.0 m/s for 10.0 miles, then at 30.0 m/s for another 10.0 miles. Part A Is your average speed 2

aliina [53]

Answer:

less than 27 m/s

Explanation:

The average speed would be total distance (10 + 10 = 20 miles = 32000 m) over total time

The time it takes you to drive the first 10 miles (16000 m) at 24m/s is

16000 / 24 = 666.67 s

The time it takes you to drive the 2nd 10 miles (16000 m) at 30 m/s is

16000 / 30 = 533.33 s

The average speed is

$v = \frac{16000 + 16000}{666.67 + 533.33} = \frac{32000}{1200} = 26.67 m/s$ < 27 m/s

So your average speed is less than 27 m/s

6 0

3 years ago

What statement about energy transfer in a wave is true?

laila [671]

Answer:

Energy moves between the particle of the medium.

Explanation:

8 0

3 years ago

A diver shines a flashlight upward from beneath the water (n=1.33) at a 36.2° angle to the vertical. At what angle does the ligh

horrorfan [7]

Answer:

The flashlight leaves the water at an angle of 51.77°.

Explanation:

if n1 = 1.33 is the refractive index of water and ∅1 is the angle at which the flashlight shine beneath the water, and n2 = 1.0 is the refractive index of air and ∅2 is the angle the flashlight leaves the water.

Then, according to Snell's law :

n1×sin(∅1) = n2×sin(∅2)

sin(∅2) = n1×sin(∅1)/n2

= (1.33)×sin(36.2)/(1.0)

= 0.7855055×379

∅2 = 51.77°

Therefore, the flashlight leaves the water at an angle of 51.77°.

7 0

3 years ago

h(t) = - 16t2 + 64t + 112 where t is the time in seconds. After how many seconds does the arrow reach it maximum height? Round t

laila [671]

Answer:

2 seconds

Explanation:

The function of height is given in form of time. For maximum height, we need to use the concept of maxima and minima of differentiation.

$h(t)=-16t^{2}+64t+112$

Differentiate with respect to t on both the sides, we get

$\frac{dh}{dt}=-32t+64$

For maxima and minima, put the value of dh / dt is equal to zero. we get

- 32 t + 64 = 0

t = 2 second

Thus, the arrow reaches at maximum height after 2 seconds.

8 0

3 years ago

An object is thrown vertically up and attains an upward velocity of 9.6 m/s when it reaches one fourth of its maximum height abo

ki77a [65]

Answer:

11.09 m/s

Explanation:

Given that an object is thrown vertically up and attains an upward velocity of 9.6 m/s when it reaches one fourth of its maximum height above its launch point.

The parameters given are:

Initial velocity U = ?

Final velocity V = 9.6 m/s

Acceleration due to gravity g = 9.8m/s^2

Let first assume that the object is thrown from rest with the velocity U, at maximum height V = 0

Using third equation of motion

V^2 = U^2 - 2gH

0 = U^2 - 2 × 9.8H

U^2 = 19.6H ........ (1)

Using the formula again for one fourth of its maximum height

9.6^2 = U^2 - 2 × 9.8 × H/4

92.16 = U^2 - 19.6/4H

92.16 = U^2 - 4.9H

U^2 = 92.16 + 4.9H ...... (2)

Substitute U^2 in equation (1) into equation (2)

19.6H = 92.16 + 4.9H

Collect the like terms

19.6H - 4.9H = 92.16

14.7H = 92.16

H = 92.16/14.7

H = 6.269

Substitute H into equation 2

U^2 = 92.16 + 4.9( 6.269)

U^2 = 92.16 + 30.72

U^2 = 122.88

U = 11.09 m/s

Therefore, the initial velocity of the object is 11.09 m/s

3 0

3 years ago