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3 years ago

A 12 kg bowling ball would require what force to accelerate down and alleyway at a rate of 3 m/s²?

1 answer:

defon3 years ago

8 0

Part 1. F= m*a
M=12kg
A= 3 m/s^2

So F = 12kg * 3 m/s^2 which means
F=36 Newton’s

Part 2. F=12000N
M= F/A
A=4 m/s^2

So M= 12000N / 4 m/s^2
Which means M=3000 kg

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3 years ago

A toy rocket is launched with an initial velocity of 12.0 m/s in the horizontal direction from the roof of a 30.0-m-tall buildin

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Solution :

The motion in the y direction.

The time taken by the toy rocket to hit the ground,

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3 years ago

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2 years ago

Which option describes nonmetals?

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3 years ago

A small branch is wedged under a 200 kg rock and rests on a smaller object. The small object that creates a pivot point is calle

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Answer:

F = 326.7 N

Explanation:

given data

mass m = 200 kg

distance d = 2 m

length L = 12 m

solution

we know force exerted by the weight of the rock that is

W = m × g ..............1

W = 200 × 9.8

W = 1960 N

and

equilibrium the sum of the moment about that is

∑Mf = F(cos∅) L - W (cos∅) d = 0

here ∅ is very small so cos∅ L = L and cos∅ d = D

so F × L - W × d = 0 .................2

put here value

F × 12 - 1960 × 2 = 0

solve it we get

F = 326.7 N

8 0

3 years ago

Read 2 more answers