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Sholpan [36]
3 years ago
10

(Sec A+tan A) (1- Sin A)Answer for 11,12

Mathematics
2 answers:
Andrews [41]3 years ago
7 0

Answer:

11.  d.  cos A.

12.  d. tan^2 A.

Step-by-step explanation:

11.

(sec A + tan A)(1 - sinA)

= sec A - sec A sin A  + tan A - sin A tan A

Convert to sine's and cosine's using sec A = 1/ cos A and tan A = sin A / cos A:

= 1/cos A -  sin A / cos A + sin A / cos A - sin^2 A / cos A

= 1 /cos A - sin^2 A / cos A

= (1 - sin^2 A) / cos A     Using  1 - sin^ A = cos^2 A:

= cos^2 A / cos A

= cos A.

12.

Now sec^2 A = 1 + tan^2 A and cosec^2 A = 1 + cot^2 A so

(1 + tan^2 A) / (1 + cot^2 A)

= sec^2 A / cosec^2 A

=    1 / cos^2 A  /   1 / sin^2 A

=  sin^2 A / cos^2 A

= tan^2  A.

KonstantinChe [14]3 years ago
5 0

Step-by-step explanation:

here is the answer for your question

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