Question

Wil-E- Coyote drops a bowling ball off a cliff to try to catch the Roadrunner. The cliff is 132m high. What is its impact velocity?​

Answer 1

Answer:

Velocity impact is 50.86 m/s.

Explanation:

If an "object of mass" "m" is dropped from "height" "h", then the "velocity" just before impact is  "v" . The "kinetic energy" before impact is equal to its "gravitational potential energy" at the height from which it was dropped: Kinetic energy = J.

$\mathrm{v}^{2}=2 \mathrm{gh}$

V is impact velocity

h height in meter = 132 m

$\text { (gis referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^{2} \text { on Earth }$

$\mathrm{V}^{2}=2 \times 9.8 \times 132$

$V^{2}=19.6 \times 132$

$V^{2}=2587.2$

$V=\sqrt{2587.2}$

V = 50.86 m/s

Velocity impact is 50.86 m/s.