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alexandr402 [8]
4 years ago
10

Why charcoal grills or chaecoal fires would not be used to hear the inside of a house

Chemistry
1 answer:
nignag [31]4 years ago
4 0
You are at risk of getting on fire

And all you will hear is fire
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1. john needs to create a buffered solution at a ph of 3.5 for his biomedical laboratory
Lunna [17]

Answer:

Use a ratio of 0.44 mol lactate to 1 mol of lactic acid  

Explanation:

John could prepare a lactate buffer.

He can use the Henderson-Hasselbalch equation to find the acid/base ratio for the buffer.

\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\3.5 = 3.86 + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\\log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 3.5 - 3.86 = -0.36\\\\\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 10^{-0.36} = \mathbf{0.44}

He should use a ratio of 0.44 mol lactate to 1 mol of lactic acid.

For example, he could mix equal volumes of 0.044 mol·L⁻¹ lactate and 0.1 mol·L⁻¹ lactic acid.

6 0
3 years ago
A class of substances known as __________ are used for their medicinal properties.
Misha Larkins [42]

Answer: Alkaloids

A class of substances known as alkaloids are used for their medicinal properties.

Explanation:

Alkaloids are small but complex organic substances with at least one nitrogen atom in its ring structure. Hence, they have strong basic properties, and are produced in naturally by some plants.

Examples of alkaloids and their medicinal properties are as follows:

- caffeine, used in certain drug and drinks to stimulate the nervous system

- morphine, used to reduce pain and induce sleep in humans.

- cocaine, nicotine etc

6 0
3 years ago
Read 2 more answers
What 2 properties make capillary action possible
Natali5045456 [20]
Cohesion and adhesion
7 0
3 years ago
Question 1 (1 point)<br> ROOTS--What is NOT a root function in plants?
Jlenok [28]

Answer:

deez nuets

Explanation:

bf gm Jr rj if dl if did fll j fll kd golf du is no u to

3 0
3 years ago
A sample of gas occupies a volume of 73.7 mL. As it expands, it does 133.7 J of work on its surroundings at a constant pressure
katen-ka-za [31]
In thermodynamics<span>, </span>work<span> performed by a system is the energy transferred by the system to its surroundings. It can be calculated by the expression:
</span>
W = PdV

Integrating,

We will have,

W = P(V2 - V1)
133.7 (1 litre-atm / 101.325 Joule) ( <span>760 Torr / atm ) </span>= 783 (V2 - .0737 )
V2 = 1.35 L

Hope this answers the question.  Have a nice day.


7 0
4 years ago
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