The answer is 1.98 × 10^22 iron (II) ions
Answer: 28.3 g/mol
Explanation:
According to the ideal gas equation:'
P= Pressure of the gas = 0.951 atm
V= Volume of the gas = 280 mL = 0.28 L (1L=1000 ml)
T= Temperature of the gas = 25°C=(25+273)K=298 K (0°C = 273 K)
R= Value of gas constant = 0.0821 Latm/K mol
To calculate the moles, we use the equation:
Thus the molar mass of the gas is 28.3 g/mol.
CaCl₂ → Ca²⁺ + 2Cl⁻
∑=1+2=3
D) 3 mol
Answer:
-205.7kj
Explanation:
Now adding reaction 2 and twice of reaction 3 and reverse of reaction 1, we get the enthalpy of the reaction.
The expression for enthalpy for the following reaction will be,
where,
n = number of moles
Now put all the given values in the above expression, we get:
Therefore, the enthalpy of the following reaction is, -205.7kj
Answer:
Two reagents that can be used to distinguish between ethane and ethyne are Tollens' reagent and ammoniacal CuCl solution.