A planet exerts a gravitational force of magnitude 4e22 N on a star. If the planet were 3 times closer to the star (that is, if
1 answer:
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Answer:
a) 0.568 kg
b) 474 kg/m³
Explanation:
Given:
Inner radius = 8.82 cm = 0.0882 m
Outer radius = 9.91 cm = 0.0991 m
Density of the liquid = 948.00 Kg/m³
a) The volume of the sphere =
or
volume of sphere = 0.0012 m³
also, volume of half sphere =
or
volume of half sphere =
or
Volume of half sphere =0.0006 m³
Now, from the Archimedes principle
Mass of the sphere = Weight of the volume of object submerged
or
Mass of the sphere = 0.0006× 948.00 = 0.568 kg
b) Now, density =
or
Density =
or
Density = 474 kg/m³
Answer:
emf will also be 10 times less as compared to when it has fallen
Explanation:
We know, from faraday's law-
and
So, as the height increases the velocity with which it will cross the ring will also increase.
Given
Now, from
From equation a and b we see that velocity when dropped from is 10 times greater when height is 40
so, emf will also be 10 times less as compared to when it has fallen