All categories

2 years ago

Which of the following mathematical operations are and are not not allowed on two quantities with different unit dimensions?

1 answer:

4 0

The following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality

To answer the question, we have to know what mathematical operations are.

<h3>What are Mathematical operations?</h3>

Mathematical operations are operations which are performed to change the value of a variable. The arithmetic mathematical operations we have are

addition,
subtraction,
multiplication,
subtraction and
equality which shows the relationship between two quantities.

Now, for two quantities with different unit dimensions, addition, subtraction and equality are not allowed because these mathematical operations require the quantities to be in the same unit dimensions

Also, for two different quantities with differnt unit dimensions, multiplication and division are allowed because these mathematical operations do not require the quantities to be in the same unit dimensions.

So, the mathematical operations that are allowed are multiplication and division while the mathematical operations that are not allowed are addition, subtraction and equality.

So, the following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality

Learn more about mathematical operations here:

brainly.com/question/26112472

You might be interested in

Let’s allow ourselves to be a little more optimistic with our bus passengers. Earlier in the movie Sandy has to make the bus jum

Roman55 [17]

Answer:

25.71486 seconds

Explanation:

t = Time taken

u = Initial velocity = 60 mph

v = Final velocity = 80 mph

s = Displacement = 0.5 mile

a = Acceleration

Converting to m/s

$60\times \dfrac{1609.34}{3600}=26.8223\ m/s$

$80\times \dfrac{1609.34}{3600}=35.7631\ m/s$

From equation of motion

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{35.7631^2-26.8223^2}{2\times \dfrac{1609.34}{2}}\\\Rightarrow a=0.34769\ m/s^2$

$v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{35.7631-26.8223}{0.34769}\\\Rightarrow t=25.71486\ s$

Time taken is 25.71486 seconds

4 0

3 years ago

A direct result of the Newlands reclamation Act was the

Lina20 [59]

I think it is building and managing of irrigation systems

3 0

3 years ago

Read 2 more answers

What is the final temperature of 0.5 kg of water initially at 18 °C after 65 kJ of

goldenfox [79]

A is the answe for the final temperatures

8 0

3 years ago

Read 2 more answers

Approximately how many atoms are there along a 9.5 cm line

uranmaximum [27]

First convert 5.5 cm to meters.

(5.5 cm / 1) x (m / 100 cm) = 0.055 m

A typical atom is about 1.0E-10 m in diameter; thus:

0.055 m / 1.0E-10 m = 5.5E8 atoms or 550,000,000 end-to-end atoms in 5.5 cm

4 0

3 years ago

A person just supports a mass of 20kg suspended from a rope.

Georgia [21]

Answer:

F = 200 N

Explanation:

Given that,

The mass suspended from the rope, m = 20 kg

We need to find the resultant force acting on the rope. The resultant force on the rope is equal to its weight such that,

F = mg

Where

g is acceleration due to gravity

Put all the values,

F = 20 kg × 10 m/s²

F = 200 N

So, the resultant force on the mass is 200 N.

7 0

2 years ago