Question

The reaction below shows how silver chloride can be synthesized.

Answer 1

Answer : The correct option is, (2) 15.0 mole

Solution : Given,

Moles of silver nitrate = 15.0 mole

The given balanced chemical reaction is,

$AgNO_3+NaCl\rightarrow NaNO_3+AgCl$

By the stoichiometry, we conclude that 1 mole of silver nitrate react with 1 mole of sodium chloride to give 1 mole of sodium nitrate and 1 mole of silver chloride.

Th ratio $AgNO_3:AgCl=1:1$

From the balanced reaction, we conclude that

As, 1 mole of silver nitrate react to give 1 mole of silver chloride

So, 15 moles of silver nitrate react to give 15 moles of silver chloride

Therefore, the number of moles of silver chloride produced are, 15.0 mole

Answer 2

$AgNO_{3} _{(aq)} + NaCl_{(aq)} ----\ \textgreater \ NaNO_{3} _{(aq)} + AgCl _{(aq)}$
mole ration of $AgCl _{(aq)} : AgNO_{3} _{(aq)}$ =  1 : 1

∴ if moles of  $AgNO_{3} _{(aq)}$ =  15.0 mol
then   "      "     $AgCl _{(aq)}$  =  15.0 mol

∴  the Option  2 is the answer.