Question

A hot iron ball is dropped into a 200 g sample of water initially at 50 degrees Celsius.

Answer 1

The answer is 60 C
Because the initial temperature is 50 C and the calculated change in temperature is 10 C. So to get the final temperature add 50 C to 10 C which gives 60 C.
The I have uploaded the complete solution to the question below.

Answer 2

Answer:

The final temperature is 60 °C

Explanation:

Step 1: Data given

Mass of the iron ball = 200 grams

Initial temperature = 50 °C

8.4 kJ of heat is transferred from the ball to the water.

The specific heat of water = 4.2 J/g°C

Step 2: Calculate the final temperature

Q = m*c*ΔT

⇒ with Q = heat is transferred from the ball to the water = 8400 J

⇒ m = the mass of the ball = 200 grams

⇒ c = the specific heat of water = 4.2 J/g°C

⇒ ΔT = T2 - T1 = T2 - 50

8400 J = 200g*4.2 J/g°C * (T2-50°C)

8400  = 840T2 - 42000

50400 = 840T2

T2 = 50800/840

T2 = 60 °C

The final temperature is 60 °C