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Tcecarenko [31]
2 years ago
7

I miss you guys... :(((A... V...., A... A...

Chemistry
1 answer:
Nostrana [21]2 years ago
5 0

hello don't be sad whoever you're missing you'll find soon

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Explain why, when the imidazole ring of histidine is protonated, the double-bonded nitrogen is the nitrogen that accepts the pro
eduard
The important thing to note is the reason why electron react is due to the instability of the electrons. All elements wants to aim the electron configuration of the noble gases. This is the most stable form in which each of the orbitals are sufficiently filled. When it comes to bonding, the order of reactivity is: alkynes > alkenes > alkanes. Alkynes are compounds with triple bonds, alkenes with double bonds and alkanes with single bonds. The single bonds are called saturated hydrocarbons. This is because they have reached stability, so it is quite difficult to react this with reducing or oxidizing agents. Alkynes and alkenes are unsaturated hydrocarbons. They readily react with reducing and oxidizing agents so as to become saturated, as well. The underlying principle for this is that single bonds contain sigma bonds which is the head-on overlapping of electrons. These is the strongest type of covalent bond. Double and triple bonds contain pi bonds which is the side overlapping of electrons orbitals. Hence, these electrons would be easily separated making it more reactive especially during protonation.
4 0
3 years ago
Bridget is in science class. Her teacher gives her two unknown substances and asks her to determine their relative pH. She place
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Answer:

d dddddddddd

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4 0
2 years ago
Uranium – 235 has a half-life of 713 million years. Would uranium – 235 or carbon – 14 be more useful for dating Cambrian time e
kenny6666 [7]
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What type of energy is present in wound-up rubber band in a toy airplane?
andriy [413]
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3 0
3 years ago
Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq
Inga [223]

Answer:

M_{acid}=0.0444M

Explanation:

Hello,

In this case, for the given reaction:

H _2 S O _4 + 2 N a O H \rightarrow 2 _H 2 O + N a _2 S O_ 4

We find a 1:2 molar ratio between the acid and the base respectively, for that reason, at the equivalence point we find:

2*n_{acid}=n_{base}

That in terms of concentrations and volumes we can compute the concentration of the acid solution:

2*M_{acid}V_{acid}=M_{base}V_{base}\\\\M_{acid}=\frac{M_{base}V_{base}}{2*V_{acid}}=\frac{0.697M*28.07mL}{2*220.1mL}\\ \\M_{acid}=0.0444M

Best regards.

5 0
3 years ago
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