Answer:
See explanation
Explanation:
Two structures are pictured in the image attached, structure 2 is a more stable structure for TeF₄ or TeCl₄ since the lone pair in the structure is present at an equatorial position. Note that the structure of the compound is based on a trigonal bipyramid but of the structure type AX4E, where the lone pair could be positioned at axial or equatorial positions as shown in the images attached.
As a result of repulsion between electron pairs, the bond distance between Te - X(axial) is greater than Te-X (equatorial). This implies that the Te - X(axial) bonds are longer than Te - X(equatorial) bonds.
In answering the question, we must take cognisance of the fact fluorine is more electronegative than chlorine. This implies that fluorine will draw more electron density towards itself than chlorine and this shortens the bond length.
The structures of the both compounds are based on a trigonal bipyramid with a bond angle of 90° for axial position and 120° for the equatorial position.
Owing to the greater electo negativity of fluorine, both the fluorine F-axial and F-equatorial bonds of TeF4 are shorter than the Cl-axial and Cl-equatorial bonds of TeCl4. Hence the axial and equatorial angles in TeF4 are smaller than the axial and equatorial bond angles in TeCl4 due to the greater electro negativity of the fluorine atom.
<span>None. Since it is dominant, both would have to show it to pass in on.</span>
Answer:
Na: 1s2 2s2 2p6 3s1
Na+: 1s2 2s2 2p6
Na+ electronic configuration resemble that of Neon( 1s2 2s2 2p6)
In general, the electronic configuration of alkali metals ions resemble that of the group zero (noble gas)
your answer is 0.00833M the volume was converted into liters
NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)
Using the molarity equation, we can find the number of moles of HCl that reacted:
molarity=mol soluteL soln
mol solute=(molarity)(L soln)
mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl
(volume converted to liters)
Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:
0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH
Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:
molarity=mol soluteL soln