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Sidana [21]
4 years ago
6

Which effect are most likely from a hurricane? Check all that apply

Chemistry
1 answer:
const2013 [10]4 years ago
5 0

The correct answers are option - A , B, D and E

Damaged homes due to flooding  

Uprooted trees due to high winds

Eroded coastline due to storm surge  

Damaged personal property due to hail

Reason -

A hurricane when strikes a coastal area causes serious hazards such as heavy rains, high winds, a storm surge, and even tornadoes. A storm surge pushes the sea water on the shore and thus causes flooding near the coast. However heavy rains cause flooding in inland areas. High winds, storm surge, flooding and tornadoes causes damaging of house, personal property and car.

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The structures of TeF4 and TeCl4 in the gas phase have been studied by electron diffraction (S. A. Shlykov, N. I. Giricheva, A.
Studentka2010 [4]

Answer:

See explanation

Explanation:

Two structures are pictured in the image attached, structure 2 is a more stable structure for TeF₄ or TeCl₄ since the lone pair in the structure is present at an equatorial position. Note that the structure of the compound is based on a trigonal bipyramid but of the structure type AX4E, where the lone pair could be positioned at axial or equatorial positions as shown in the images attached.

As a result of repulsion between electron pairs, the bond distance between Te - X(axial) is greater than Te-X (equatorial). This implies that the Te - X(axial) bonds are longer than Te - X(equatorial) bonds.

In answering the question, we must take cognisance of the fact fluorine is more electronegative than chlorine. This implies that fluorine will draw more electron density towards itself than chlorine and this shortens the bond length.

The structures of the both compounds are based on a trigonal bipyramid with a bond angle of 90° for axial position and 120° for the equatorial position.

Owing to the greater electo negativity of fluorine, both the fluorine F-axial and F-equatorial bonds of TeF4 are shorter than the Cl-axial and Cl-equatorial bonds of TeCl4. Hence the axial and equatorial angles in TeF4 are smaller than the axial and equatorial bond angles in TeCl4 due to the greater electro negativity of the fluorine atom.

7 0
3 years ago
A widow's peak is a V-shaped area of the hairline in the center of the forehead. The allele for having a widow's peak is dominan
Flauer [41]
<span>None. Since it is dominant, both would have to show it to pass in on.</span>
8 0
3 years ago
Read 2 more answers
High-level radioactive waste requires deep burial because it is explosive. TRUE FALSE
Norma-Jean [14]
True.................
8 0
4 years ago
Read 2 more answers
When Na forms an ion it loses its outer electron to become Na+. Write the electron configuration for Na and Na+. What element do
Otrada [13]

Answer:

Na: 1s2 2s2 2p6 3s1

Na+: 1s2 2s2 2p6

Na+ electronic configuration resemble that of Neon( 1s2 2s2 2p6)

In general, the electronic configuration of alkali metals ions resemble that of the group zero (noble gas)

3 0
4 years ago
You titration 5.0 mL of HCl with 0.010 M NaOH. You find the end point of your titration occurs when 12.0 mL of NaOH has been add
Nookie1986 [14]

your answer is 0.00833M the volume was converted into liters

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Using the molarity equation, we can find the number of moles of HCl that reacted:

molarity=mol soluteL soln

mol solute=(molarity)(L soln)

mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl

(volume converted to liters)

Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:

0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH

Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:

molarity=mol soluteL soln

5 0
3 years ago
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