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Nesterboy [21]
3 years ago
11

How many moles of H2O are needed to react with a mole of 3.0 of Na?​

Chemistry
1 answer:
AveGali [126]3 years ago
5 0

Answer: 3.0 moles of water (H_2O)  are needed to react with a mole of 3.0 of Na

Explanation:

The balanced chemical reaction of sodium with water is as follows:

2Na+2H_2O\rightarrow 2NaOH+H_2

According to stoichiometry:

2 moles of sodium (Na) reacts with = 2 moles of water (H_2O)

Thus 3.0 moles of sodium (Na) reacts with = \frac{2}{2}\times 3.0=3.0 moles of water (H_2O)

3.0 moles of water (H_2O)  are needed to react with a mole of 3.0 of Na

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You need to convert mass to moles (divide by molar mass):

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To figure out which reactant is limiting, divide the actual moles by the corresponding coefficient in the reaction:

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O2 is the lower number, so it is the limiting reactant. From the reaction we know it takes 2 moles of O2 to react with each mole of CH4. Therefore, for however many moles of O2 we actually have, half as many moles of CH4 will react. Since we have 0.16 mol of O2, only 0.08 mol of CH4 will react, leaving behind 0.31 - 0.08 = 0.23 mol of CH4.

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0.23 x 16 = 3.68g

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<h3>Answer:</h3>

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