Friction , as the angle gets huger and higher , this is less and less normal force into the inclined plane .
Answer:
तिकडी एकच
Explanation:
आप सल क्ल वल दन रव दंचंबी एक गम ok plz
Well,
First of all, this isn't physics in my opinion; this is Astronomy.
In the mesosphere, there exists a high concentration of ions. This region is called the ionosphere.
Answer:
F = mv²/(18d)
7
Explanation:
Momentum before collision = momentum after collision
mv = m(v/3) + (4m) V
v = v/3 + 4V
4V = 2v/3
V = v/6
The acceleration of the block is:
v² = v₀² + 2aΔx
(0 m/s)² = (v/6)² + 2ad
2ad = -v²/36
a = -v²/(72d)
The friction force is therefore:
∑F = ma
-F = (4m) (-v²/(72d))
F = mv²/(18d)
The energy dissipated during the collision is:
ΔE = 1/2 mv² − (1/2 m(v/3)² + 1/2 (4m)(v/6)²)
ΔE = 1/2 mv² − (1/18 mv² + 1/18 mv²)
ΔE = 1/2 mv² − 1/9 mv²
ΔE = 7/18 mv²
The energy dissipated by the friction force:
W = Fd
W = 1/18 mv²
The ratio is:
ΔE / W
(7/18 mv²) / (1/18 mv²)
7
