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Andreyy89
3 years ago
10

What is carnot engine.express the relation for its efficiency?​

Physics
2 answers:
patriot [66]3 years ago
6 0

Answer:

Explanation:

The Carnot cycle is a special case of a thermodynamic cycle that produces an ideal gas and consists of two isothermal  processes and two adiabatic processes. This cycle is a theoretical solution given by Sadi Karnot to refine heat engines for their efficient use.

The formula for the coefficient of efficiency is:

η = (Q₁ - Q₂) / Q₁ = (T₁ - T₂) / T₁

Where Q₁ is is the amount of heat of the heater supplied to the working body and Q₂ is the amount of heat that the working body transfers to the refrigerator according to this T₁ is the temperature of the heater T₂ is the temperature of the refrigerator.

This formula provides a theoretical limit for the maximum value of the coefficient of efficiency of heat engines.

God is with you!!!

bazaltina [42]3 years ago
5 0

Answer:

The Carnot cycle is a special case of a thermodynamic cycle that produces an ideal gas and consists of two isothermal  processes and two adiabatic processes. This cycle is a theoretical solution given by Sadi Karnot to refine heat engines for their efficient use.

The formula for the coefficient of efficiency is:

η = (Q₁ - Q₂) / Q₁ = (T₁ - T₂) / T₁

Where Q₁ is is the amount of heat of the heater supplied to the working body and Q₂ is the amount of heat that the working body transfers to the refrigerator according to this T₁ is the temperature of the heater T₂ is the temperature of the refrigerator.

This formula provides a theoretical limit for the maximum value of the coefficient of efficiency of heat engines.

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Explanation: To solve this problem we have to use the relationship given by De Broglie as:

λ =p/h where p is the momentum and h the Planck constant

if we consider the energy given by acceleration tube for the electrons given by: E: e ΔV so is equal to kinetic energy of electrons p^2/2m

Finally we have:

eΔV=p^2/2m= h^2/(2*m*λ^2)

replacing we obtained the above values.

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How to understand that an inductor behaves like short circuit and capacitor like an open circuit in steady state in a network?
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Some liquid is poured into a burrete so that it reads 14cm³.50 drops were run each of volume 0.1cm³ .
nika2105 [10]

Given :

Liquid is poured into a burrete so that it reads 14cm³.

50 drops were run each of volume 0.1cm³ .

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The volume of liquid in burrete after 50 drops.

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Initial volume in burrete, V = 14 cm³.

Now, volume left after droping 50 drops are :

L = V - 50v\\\\L = 14 - 50\times 0.1 \ cm^3 \\\\L = 9 \ cm^3

Therefore, the volume left in burrete is 9 cm³ .

5 0
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Are most plants and animals single-cell organisms
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3 years ago
Read 2 more answers
A 50g ball is released from rest 1.0 above the bottom of thetrack
ludmilkaskok [199]

Answer:

The maximum height of the ball is 2 m.

Explanation:

Given that,

Mass of ball = 50 g

Height = 1.0 m

Angle = 30°

The equation is

y=\dfrac{1}{4}x^2

We need to calculate the velocity

Using conservation of energy

\Delta U_{i}+\Delta K_{i}=\Delta K_{f}+\Delta U_{f}

Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero

\Delta U_{i}=\Delta K_{f}

Put the value into the formula

mgh=\dfrac{1}{2}mv^2

Put the value into the formula

50\times10^{-3}\times9.8\times1.0=\dfrac{1}{2}\times50\times10^{-3}\times v^2

v^2=\dfrac{2\times50\times10^{-3}\times9.8\times1.0}{50\times10^{-3}}

v=\sqrt{19.6}

v=4.42\ m/s

We need to calculate the maximum height of the ball

Using again conservation of energy

\dfrac{1}{2}mv^2=mgh

Here, h = y highest point

Put the value into the formula

\dfrac{1}{2}\times50\times10^{-3}\times(4.42)^2=50\times10^{-3}\times9.8\times h

y=\dfrac{0.5\times(4.42)^2}{9.8}

y=0.996\ m

Put the value of y in the given equation

y=\dfrac{1}{4}x^2

x^2=4\times0.996

x=\sqrt{4\times0.996}

x=1.99\ m\ \approx 2 m

Hence, The maximum height of the ball is 2 m.

4 0
3 years ago
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