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Leviafan [203]
3 years ago
11

The periodic table tells you how many grams are in a mole of atoms of any

Chemistry
1 answer:
svetlana [45]3 years ago
3 0

Answer:

I believe it is B. molar mass...

Explanation:

Hope this is right!

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If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is
mojhsa [17]

Answer:

MnO- Manganese Oxide

Explanation:

Empirical formula: This is the formula that shows the ratio of elements

present in a  

compound.

   

How to determine Empirical formula

1. First arrange the symbols of the elements present in the compound

alphabetically to  determine the real empirical formula. Although, there

are exceptions to this rule, E.g H2So4

2. Divide the percentage composition by the mass number.

3. Then divide through by the smallest number.

4. The resulting answer is the ratio attached to the elements present in

a compound.

           

                                                                              Mn                         O    

                         

% composition                                                      72.1                      27.9    

                       

Divide by mass number                                       54.94                     16  

                                 

                                                                               1.31                      1.74    

                       

Divide by the smallest number                         1.31                      1.31                          

                                                                               1                    1.3

                                                 

The resulting ratio is 1:1

 

Hence the Empirical formula is MnO, Manganese oxide

8 0
3 years ago
2+
Reika [66]

Answer:

[ar]5s1401

Explanation:

nanbsbshdhshhshshshhd

8 0
3 years ago
Which of the following metals will react with water to produce a metal hydroxide and hydrogen gas? (2 points)
vazorg [7]
The answer would be the first option - k
8 0
3 years ago
Read 2 more answers
Suppose that X represents an arbitrary cation and that Y represents an anionic species. Using the charges indicated in the super
dmitriy555 [2]

Answer:

See explanation.

Explanation:

Hello!

In this case, when having the cationic and anionic species with the specified charges, in order to abide by the net charge rule, we need to exchange the charges in the form of subscripts and without the sign, just as shown below:X^{m+}Y^{n-}\rightarrow X_nY_m

Thus, for all the given combinations, we obtain:

- Y⁻

X^+Y^-\rightarrow XY\\\\X^{2+}Y^-\rightarrow XY_2\\\\X^{3+}Y^-\rightarrow XY_3

- Y²⁻

X^+Y^{2-}\rightarrow X_2Y\\\\X^{2+}Y^{2-}\rightarrow X_2Y_2\rightarrow XY\\\\X^{3+}Y^{2-}\rightarrow X_2Y_3

- Y³⁻

X^+Y^{3-}\rightarrow X_3Y\\\\X^{2+}Y^{3-}\rightarrow X_3Y_2 \\\\X^{3+}Y^{3-}\rightarrow X_3Y_3\rightarrow XY

Best regards!

8 0
3 years ago
Some one help me with this will give brainliest
Alona [7]
14. C
15. B
16. D
17. D
18. I am not sure sorry.<span />
3 0
3 years ago
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