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3 years ago

The periodic table tells you how many grams are in a mole of atoms of any

Chemistry

1 answer:

svetlana [45]3 years ago

3 0

Answer:

I believe it is B. molar mass...

Explanation:

Hope this is right!

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Pure water and pure salt are poor conductors of electricity. When salt is dissolved in water, the resulting solution conducts el

castortr0y [4]

Answer:

you are right

Explanation:

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3 years ago

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A hiker has packed a bag of chips as a snack. At the start of the hike the pressure was 1.5 atm and the temperature was 35*C. At

Mazyrski [523]

According to Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
Mathematically for initial and final states it is expressed as,

P₁ / T₁ = P₂ / T₂ ----- (1)
Data Given;
P₁ = 1.5 atm

T₁ = 35 °C + 273 = 308 K

P₂ = ?

T₂ = 0 °C + 273 = 273 K

Solving Eq. 1 for P₂,

P₂ = P₁ T₂ / T₁

Putting values,
P₂ = (1.5 atm × 273 K) ÷ 308 K

P₂ = 1.32 atm
Result:
As the temperature is decreased so the pressure also decreases from 1.5 atm to 1.32 atm. Therefore the bag will contract.

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3 years ago

Splash (TikTok edition) A: Now that you know how my ice be B: know how the ice be

Annette [7]

A: Now that you know how my ice be.

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3 years ago

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Given the following formula for calculating the ionization energy of one-electron species such as Li2+, He+, and H, calculate th

Yuki888 [10]

Answer:

The answer is " $32819.9 \ \frac{J}{mol}\\\\$ "

Explanation:

$Boron: 5^{B}\to 1s^2 2s^2 2p^1$

$\Delta E=-2.18\times 10^{-18}\ \frac{J}{atom}\ (\frac{1}{\infity^2}-\frac{1}{n^2_{initial}})(z^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\$

$=-2.18\times 10^{-18}\ \frac{J}{atom}\ (0-\frac{1}{1})(5^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\ =2.18\times 10^{-18}\times 25 \times 6.022\times 10^{23}\ (\frac{J}{mol})\\\\ =328.199 \times 10^{5}\ (\frac{J}{mol})\\\\ =32819 \times 10^{3}\ (\frac{J}{mol})\\\\ =32819.9 \ (\frac{J}{mol})\\\\$

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3 years ago

Potassium + water → potassium hydroxide + hydrogen formula

kvasek [131]

Answer:

If you help I'll help you deal?

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2 years ago