Question: The force between a pair of 0.005 C is 750 N. What is the distance between them?
Answer:
17.32 m
Explanation:
From coulomb's Law,
F = kqq'/r²........................... Equation 1
Where F = Force between the force, q' and q = both charges respectively, k = coulomb's constant, r = distance between both charges.
make r the subject of the equation above
r = √(kqq'/F)..................... Equation 2
From the question,
Given: q = q' = 0.005 C, F = 750 N
Constant: k = 9.0×10⁹ Nm²/C².
Substitute these values into equation 2
r = √(9.0×10⁹×0.005×0.005/750)
r = √(300)
r = 17.32 m.
Hence the distance between the pair of charges = 17.32 m
Explanation:
d) Magnetic force is the power that pulls materials together (magnet e. g iron)
an example :how magnet can pick up a coin.
e) frictional force produces when two surfaces are in contact with each other.
effects of friction : I) it produces heat
II) it causes loss in power.
The new weight is 273.8 N
Explanation:
The weight of an object on Earth is given by
![W=mg](https://tex.z-dn.net/?f=W%3Dmg)
where
m is the mass of the object
g is the acceleration of gravity
The acceleration of gravity at the Earth's surface can be rewritten as
![g=\frac{GM}{R^2}](https://tex.z-dn.net/?f=g%3D%5Cfrac%7BGM%7D%7BR%5E2%7D)
where
G is the gravitational constant
M is the Earth's mass
R is the Earth's radius
Substituting into the previous equation,
![W=\frac{GMm}{R^2}](https://tex.z-dn.net/?f=W%3D%5Cfrac%7BGMm%7D%7BR%5E2%7D)
We said that in normal conditions, the weight of the person is 730 N:
![W=\frac{GMm}{R^2}=730 N](https://tex.z-dn.net/?f=W%3D%5Cfrac%7BGMm%7D%7BR%5E2%7D%3D730%20N)
Later, we are said that:
- The mass of the Earth increases by a factor of 6,
![M'=6M](https://tex.z-dn.net/?f=M%27%3D6M)
- The radius of the Earth increases by a factor of 4,
![R'=4R](https://tex.z-dn.net/?f=R%27%3D4R)
Substituting into the equation, we find the new weight of the person in these conditions:
![W'=\frac{G(6M)m}{(4R)^2}=\frac{6}{16}(\frac{GMm}{R^2})=\frac{3}{8}W](https://tex.z-dn.net/?f=W%27%3D%5Cfrac%7BG%286M%29m%7D%7B%284R%29%5E2%7D%3D%5Cfrac%7B6%7D%7B16%7D%28%5Cfrac%7BGMm%7D%7BR%5E2%7D%29%3D%5Cfrac%7B3%7D%7B8%7DW)
So, the new weight is 3/8 of the original weight, therefore:
![W'=\frac{3}{8}(730)=273.8 N](https://tex.z-dn.net/?f=W%27%3D%5Cfrac%7B3%7D%7B8%7D%28730%29%3D273.8%20N)
Learn more about gravity:
brainly.com/question/1724648
brainly.com/question/12785992
#LearnwithBrainly
Answer:
True plz thank me this is the answer
Answer:
The frequency of the green light is ![6x10^{14}Hz](https://tex.z-dn.net/?f=6x10%5E%7B14%7DHz)
Explanation:
The visible region is part of the electromagnetic spectrum, any radiation of that electromagnetic spectrum has a speed of
in the vacuum.
Green light is part of the visible region. Therefore, the frequency can be determined by the following equation:
(1)
Where c is the speed of light,
is the wavelength and
is the frequency.
Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave (that is a magnetic field perpendicular to an electric field).
Then,
can be isolated from equation 1
(2)
Notice that it is necessary to express the wavelength in units of meters.
⇒ ![5x10^{-7}m](https://tex.z-dn.net/?f=5x10%5E%7B-7%7Dm)
Hence, the frequency of the green light is ![6x10^{14}Hz](https://tex.z-dn.net/?f=6x10%5E%7B14%7DHz)