A paper airplane used to study wing designs is an example of a ?

Physics

2 answers:

Licemer1 [7]3 years ago

8 0

Option A, many mental illnesses are used to define an individual, is the right answer.

A disease is a critical unusual condition that adversely influences the structure or performance of a part or full of a person or animals, and that is not due to any outside harm. Therefore, patients suffering from these conditions are called medical disease that can be cured by using medicines. Whereas, mental illness is a behavioral or imaginative exemplar that creates notable suffering or impairment of bodily functions. Thus, the main difference between labeling a person with medical illness and mental illness is that many mental disorders are employed to describe an individual,

kow [346]3 years ago

7 0

Model I'm guessing. Coz that's using an object to explain

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A 1,200 kg car rolls down a hill with its brakes off and transmission in neutral. At one moment it is moving 5.0 m/s. A little l

Y_Kistochka [10]

The change in kinetic energy of the car is equivalent to the change in its potential energy. Thus:
K.E = P.E
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3 years ago

The eye of the Atlantic giant squid has a diameter of 3.50 × 10^2 mm. If the eye

Lunna [17]

Answer:

q = 224 mm, h ’= - 98 mm, real imagen

Explanation:

For this exercise let's use the constructor equation

$\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

where f is the focal length, p and q are the distance to the object and the image respectively.

In a mirror the focal length is

f = R / 2

indicate us radius of curvature is equal to the diameter of the eye

R = 3,50 10² mm

f = 3.50 10² /2 = 1.75 10² mm

they also say that the distance to the object is p = 0.800 10³ mm

1 / q = 1 / f - 1 / p

1 / q = 1 / 175 - 1 /800

1 / q = 0.004464

q = 224 mm

to calculate the size let's use the magnification ratio

m = $\frac{h'}{h} = - \frac{q}{p}$

h '= $- \frac{q}{p} \ h$

h ’= - 224 350 / 800

h ’= - 98 mm

in concave mirrors the image is real.

3 0

3 years ago

A golf ball is released from rest from the top of a very tall building. Choose a coordinate system whose origin is at the starti

Zigmanuir [339]

Answer:

Velocity of the ball after 3.04 (s) = 29.79 (m/s)

Explanation:

From the free fall movement we have the following formulas: $Vf^{2} = Vo^{2} - 2gh$ and $h=Vo*t - \frac{g*t^{2} }{2}$ , First we need to find the height to time iqual to 3.04 s using the formula: $h=Vo*t - \frac{g*t^{2} }{2}$ and remember that golf ball was released from the rest (Vo= 0 (m/s)) so $h= (0 (m/s))*(3.04 (s)) - \frac{9.8 (m/s^2)*(3.04 (s))^{2} }{2}$ , we get: h = -45.28 (m) with the height that we have got, now the velocity of the ball is calculate using $Vf^{2} = Vo^{2} - 2gh$ solving for Vf, we get: $Vf = \sqrt{Vo^{2}-2*g*h }$ replacing the values given $Vf = \sqrt{(0 m/s)^{2}-2*(9.8 m/s^2)*(-45.28 m) }$ , so we get: Vf = 29.79 (m/s).