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2 years ago

Question 2: Start-Up

Physics

1 answer:

yuradex [85]2 years ago

7 0

Answer:

The car starts moving in the positive direction at x = 0.2 seconds. Initially it moves very little, but it covers a greater distance with each time increment.

Explanation:

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Joe drove at the speed of 45 miles per hour for a certain distance. He then drove at the speed of 55 miles per hour for the same

Snowcat [4.5K]

Answer:

$v_{avg} = 49.5 mph$

Explanation:

Let the distance moved by Joe is "d"

so the time taken by him to drove it by speed 45 mph is given as

$t_1 = \frac{d}{v_1}$

$t_1 = \frac{d}{45}$

now the same distance is traveled by him with speed 55 mph

so the time taken by him

$t_2 = \frac{d}{55}$

so total time taken by him for complete distance 2d

$t = t_1 + t_2$

$t = \frac{d}{45} + \frac{d}{55}$

$t = 0.0404 d$

now the average speed is given as

$v_{avg} = \frac{2d}{t}$

$v_{avg} = \frac{2d}{0.0404d}$

$v_{avg} = 49.5 mph$

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3 years ago

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We can classify both the shovel and the garden trowel as compound machines. This is because each garden tool contains two simple

Roman55 [17]

Hello,

I believe they are a lever and a wedge.

I hope this helps!

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3 years ago

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Explain how wavelength and frequency are important in determining the type of light.

asambeis [7]

It is important to note that the electromagnetic spectrum has a variety of wavelength and frequency of light in it. Some lights we can see, while others are not visual to our naked eye. It is actually very important to determine the kind of light as different lights have different wavelengths and frequencies. some lights are of very high frequency like the gamma rays, while others are of far lower frequency. <span />

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3 years ago

In which situation is a person doing work on an object?

Hunter-Best [27]

Answer:

the answer is A. A school crossing guard raises a stop sign that weigh 10 N

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2 years ago

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A small 0.14 kg metal ball is tied to a very light (essentially massless) string that is 0.9 m long. The string is attached to t

Vsevolod [243]

Answer:

a) v=2.743m/s

b) $a_c = 8.363m/s^2$

c) T=2.543N

Explanation:

First, calculate the height of the ball at the starting point:

$y' = 0.9cos(55)$

$y' = 0.516$

At this point, just in the moment the ball is released, all the energy of the system is potencial gravitational energy. When it is at the bottom all the potencial energy is transformed into kinetic energy:

$E_p=E_k\\mgh=\frac{mv^2}{2}$

Solving for v:

$v=\sqrt{2gh}$

if h is the height loss: (l-y')

v=2.743m/s

The centripetal acceleration is the acceleration caused by the tension force exercised by the string, and is pointing outside of the trayectory path (at the lowest point, directly dawn):

$a_c=\frac{v^2}{r}$

$a_c = 8.363m/s^2$

To calculate tension, just make the free body diagram of forces in the ball, noticing the existence of the centripetal acceleration:

$\sum{F_y}=ma_c=T-W\\T=ma_c+W\\T=m(a_c+g)\\T=0.14(8.363+9.8)\\T=2.543N$

4 0

3 years ago