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Svetlanka [38]
2 years ago
7

3. A train covers 168 km in 4 hours. How much distance will it cover in 80 minutes?

Physics
1 answer:
Kay [80]2 years ago
4 0

Answer:

56km

Explanation:

168 ÷ 240 = 0.7

0.7 × 80 = 56km

240 is the amount of minutes in 4 hours.

We divided 168 by 240 to get the distance covered in 1 minute. Afterwards, we needed 80 minutes so we multiplied the answer by 80.

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A gas is compressed from 600cm3 to 200cm3 at a constant pressure of 450kPa . At the same time, 100J of heat energy is transferre
Paraphin [41]

Answer: 80J

Explanation:

According to the first principle of thermodynamics:  

<em>"Energy is not created, nor destroyed, but it is conserved."  </em>

Then this priciple (also called Law) relates the work and the transferred heat exchanged in a system through the internal energy U, which is neither created nor destroyed, it is only transformed. So, in this especific case of the compressed gas:

\Delta U=Q+W  (1)

Where:

\Delta U is the variation in the internal (thermal) energy of the system (the value we want to find)

Q=-100J is the heat transferred out of the gas (that is why it is negative)

W is the work is done on the gas (as the gas is compressed, the work done on the gas must be considered positive )

On the other hand, the work done on the gas is given by:

W=-P \Delta V  (2)

Where:

P=450kPa=450(10)^{3}Pa is the constant pressure of the gas

\Delta V=V_{f}-V_{i} is the variation in volume of the gas

In this case the initial volume is V_{i}=600{cm}^{3}=600(10)^{-6}m^{3} and the final volume is V_{f}=200{cm}^{3}=200(10)^{-6}m^{3}.

This means:

\Delta V=200(10)^{-6}m^{3}-600(10)^{-6}m^{3}=-400(10)^{-6}m^{3}  (3)

Substituting (3) in (2):

W=-450(10)^{3}Pa(-400(10)^{-6}m^{3})  (4)

W=180J  (5)

Substituting (5) in (1):

\Delta U=-100J+180J  (6)

Finally:

\Delta U=80J  This is the change in thermal energy in the compression process.

8 0
3 years ago
If a car is speeding up,its initial speed is ______than its final speed
Karolina [17]
Initial speed is less than final speed
5 0
3 years ago
What two major uses does this (H-R)diagram have for astronomers?
EastWind [94]
66666666666666666666666666666666666666666666666666666666666666666666666666666666666666

7 0
2 years ago
4.00 kg glass coffee cup is 30.0°C at room temperature. It is then plunged into hot dishwater at a temperature of 90.0°C, as sho
statuscvo [17]

Answer:

Q = 200800 Joules.

Explanation:

Given the following data;

Mass = 4kg

Initial temperature = 30.0°C

Final temperature = 90.0°C

Specific heat capacity of glass = 837 J/kg°C

To find the quantity of heat absorbed;

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 90 - 30

dt = 60°C

Substituting the values into the equation, we have;

Q = 4*837*60

Q = 200800 Joules.

Therefore, the amount of heat absorbed is 200800 Joules.

8 0
3 years ago
A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.625 kg mass attached to the other end. The pu
dalvyx [7]

Answer:

The frictional torque is \tau  = 0.2505 \ N \cdot m

Explanation:

From the question we are told that

   The mass attached to one end the string is m_1 =  0.341 \ kg

   The mass attached to the other end of the string is  m_2 =  0.625 \ kg

    The radius of the disk is  r = 9.00 \ cm  = 0.09 \ m

At equilibrium the tension on the string due to the first mass is mathematically represented as

      T_1 =  m_1 *  g

substituting values

      T_1 =  0.341 * 9.8

      T_1 =  3.342 \ N

At equilibrium the tension on the string due to the  mass is mathematically represented as

      T_2 =  m_2 *  g

     T_2 = 0.625 * 9.8

      T_2 = 6.125 \ N

The  frictional torque that must be exerted is mathematically represented as

      \tau  =  (T_2 * r ) - (T_1 * r )

substituting values  

     \tau  =  ( 6.125 * 0.09 ) - (3.342  * 0.09 )

     \tau  = 0.2505 \ N \cdot m

5 0
3 years ago
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