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solong [7]
3 years ago
6

In physical change the make up of matter is changedWho or false

Chemistry
2 answers:
Anni [7]3 years ago
7 0

Answer:

True, but the substance is not transformed into another, the same is usually reversible.

Harrizon [31]3 years ago
4 0

Answer:

False

That is a chemical change

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g If 50.0 mL of a 0.75 M acetic acid solution is titrated with 1.0 M sodium hydroxide, what is the pH after 10.0 mL of NaOH have
V125BC [204]

Answer:

pH = 2.66

Explanation:

  • Acetic Acid + NaOH → Sodium Acetate + H₂O

First we <u>calculate the number of moles of each reactant</u>, using the <em>given volumes and concentrations</em>:

  • 0.75 M Acetic acid * 50.0 mL = 37.5 mmol acetic acid
  • 1.0 M NaOH * 10.0 mL = 10 mmol NaOH

We<u> calculate how many acetic acid moles remain after the reaction</u>:

  • 37.5 mmol - 10 mmol = 27.5 mmol acetic acid

We now <u>calculate the molar concentration of acetic acid after the reaction</u>:

27.5 mmol / (50.0 mL + 10.0 mL) = 0.458 M

Then we <u>calculate [H⁺]</u>, using the<em> following formula for weak acid solutions</em>:

  • [H⁺] = \sqrt{C*Ka}=\sqrt{0.458M*1.76x10^{-5}}
  • [H⁺] = 0.0028

Finally we <u>calculate the pH</u>:

  • pH = -log[H⁺]
  • pH = 2.66
8 0
3 years ago
Which chemical formula shows two atoms of iron (Fe) and three atoms of oxygen (O)?
Taya2010 [7]
Fe  O
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5 0
3 years ago
What are salt ? How they are used
Leno4ka [110]
There is different types of salt.
1)table salt
2)lime salt
7 0
3 years ago
A student weighs out a 2.23 g sample of KF, transfers it to a 300 ml volumetric flask, adds enough water to dissolve it and then
densk [106]
Answer: i d8nt kn09.
7 0
3 years ago
Effective nuclear charge, Zeff, is defined as:
Alborosie

Answer:

The effective nuclear charge for a valence electron in oxygen atom: Z_{eff} = 4.55

Explanation:

Effective nuclear charge  [Z_{eff}] is the net nuclear charge experienced by the electron in a given atom. It is always less than the actual charge of the nucleus [Z], due to shielding by electrons in the inner shells.

<em>It is equal to the difference between the actual nuclear charge or the atomic number (Z) and the shielding constant (s).  </em>

\Rightarrow Z_{eff} = Z - s

<u>For an oxygen atom</u>-

Electron configuration: (1s²) (2s² 2p⁴)

<em>The atomic number (actual nuclear charge): </em>Z = 8

The shielding constant (s) for a valence electron can be calculated by using the Slater's rules:

⇒ s = 5 × 0.35 + 2 × 0.85 = 1.75 + 1.7 = 3.45

<u><em>Therefore, the effective nuclear charge for a valence electron in oxygen atom is:</em></u>

Z_{eff} = Z - s = 8 - 3.45 = 4.55

<u>Therefore, the effective nuclear charge for a valence electron in oxygen atom:</u> Z_{eff} = 4.55

6 0
3 years ago
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