You must know the concentration of the acetic acid. Suppose the concentration is 0.1 M. The solution is as follows:
CH₃COOH → CH₃COO⁻ + H⁺
I 0.1 0 0
C -x +x +x
E 0.1 - x x x
Ka = (x)(x)/(0.1 - x)
1.8×10⁻⁵ = x²/(0.1 - x)
Solving for x,
x = 1.333×10⁻³ = H⁺
pH = -log[H⁺] = -log(1.333×10⁻³)
pH = 2.88
Answer:
CuSO4(aq)
Explanation:
The aqueous form of copper sulfate will conduct electricity.
The Solid form will not be a good conductor.
C₅H₁₂ will not conduct electricity
CO₂ will not conduct electricity
- Copper sulfate is an ionic compound
- In aqueous solutions or molten forms, ionic compounds can conduct an electric current using free mobile ions as carriers.
- This way, they are electrolytes.
- In solid state, the ions are arranged into a crystal lattice and will not conduct a current of electricity.