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4 years ago

6

A solid sphere of uniform density starts from rest and rolls without slipping down an inclined plane with angle θ = 30°. The sph

ere has mass M = 8 kg and radius R = 0.19 m . The coefficient of static friction between the sphere and the plane is μ = 0.64. What is the magnitude of the frictional force on the sphere?

1 answer:

ale4655 [162]4 years ago

7 0

Answer:

40N

Explanation:

frictional force = mgsin©

frictional force = 8*10*sin30

frictional force = 8*10*0.5= 40N//

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iragen [17]

30.1 N

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Given:

$W_1 = 16\:\text{N}$

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<u>Forces</u><u> </u><u>involving</u><u> </u><u>W1</u><u>:</u>

$x:\:\:\:-T_1 + T_3\cos \alpha = 0\:\: \\ \text{or}\:\:T_2 = T_3\cos \alpha\:\:\:\:\:(1)$

$y:\:\:\:T_3\sin \alpha - W_1 = 0\:\:\: \\ \text{or}\:\:\:T_3\sin \alpha = W_1\:\:\:\:\:\:(2)$

<u>Forces</u><u> </u><u>involving</u><u> </u><u>W2</u><u>:</u>

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