Answer:
Explanation:
To solve this problem we use the formula for accelerated motion:
We will take the initial position as our reference (
) and the downward direction as positive. Since the rock departs from rest we have:
Which means our acceleration would be:
Using our values:
The only common property is that both of those things are comprised of H2O.
<span>v=u+at</span>
<span>
0=5.0283−9.8×t</span><span>
t=0.5130sec</span><span>
Total time = 2t = 1.0261 sec</span>
Answer:
Explanation:
given that
Radius =0.75m
Cnet=0.13nC
a. Electric field inside the sphere located 0.5m from the center of the sphere.
The electric field located inside the sphere is zero.
b. The electric field located 0.25m beneath the sphere.
Since the radius is 0.75m
Then, the total distance of the electric field from the centre of the circle is 0.75+0.25=1m
Then
E=kq/r2
K=9e9Nm2/C2
q=0.13e-9C
r=1m
Then,
E= 9e9×0.13e-9/1^2
E=1.17N/C. Q.E.D
