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Zinaida [17]
3 years ago
10

Aliens come blasting into our solar system and wipe out everything but the Sun, the Earth, and Jupiter. Discuss (conceptually) w

here the center of mass of the new, smaller solar system is now roughly located. Why
Physics
1 answer:
KATRIN_1 [288]3 years ago
4 0

Answer:

There is no short answer.

Explanation:

In theory, the gravitational pull between the planets depends on their total mass and the distance between them. The sun has a mass of 1.989x10^{30} kg, Jupiter has a mass of 1.898x10^{27} kg and Earth has a mass of 5.972x10^{24} kg.

Earth is closer to Jupiter than it is to the sun. The other planets that are behind jupiter are gone so that means the sun's pulling force's effect on jupiter is increased drastically since there is no force the balance that and that means that jupiter is going to get closer to earth.

The new center of mass of the new solar system is roughly located between earth and the sun, closer to earth.

I hope this answer helps.

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Zach, whose mass is 90 kg , is in an elevator descending at 12 m/s . the elevator takes 3.0 s to brake to a stop at the first fl
sweet-ann [11.9K]
Finding out the acceleration 12/3 = 4m/s^2
thus it is descending so the actual acceleration would be 9.8-4 = 5.8 m/s^2
the weight will be 90*5.8 = 522 N
522/9.8 = 53.2 kg
7 0
3 years ago
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What's the difference and similarity between O2 and 2 O ?
nasty-shy [4]
O2 refers to two oxygen atoms bonded together, while 2 O refers to two oxygen atoms that are not bonded to each other. They both have two oxygen atoms, but in O2, the oxygen atoms are bonded, while in 2O, the atoms are not.
4 0
3 years ago
Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23
Sloan [31]

Answer:

The ratio is   \frac{T_1}{T_2}  = 3.965

Explanation:

From the question we are told that

   The  radius of Phobos orbit is  R_2 =  9380 km

    The radius  of Deimos orbit is  R_1  =  23500 \  km

Generally from Kepler's third law

    T^2 =  \frac{ 4 *  \pi^2 *  R^3}{G * M  }

Here M is the mass of Mars which is constant

        G is the gravitational  constant

So we see that \frac{ 4 *  \pi^2  }{G * M  } =  constant

   

    T^2 = R^3   *  constant      

=>  [\frac{T_1}{T_2} ]^2 =  [\frac{R_1}{R_2} ]^3

Here T_1 is the period of Deimos

and  T_1 is the period of  Phobos

So

      [\frac{T_1}{T_2} ] =  [\frac{R_1}{R_2} ]^{\frac{3}{2}}

=>    \frac{T_1}{T_2}  =  [\frac{23500 }{9380} ]^{\frac{3}{2}}]

=>    \frac{T_1}{T_2}  = 3.965

   

8 0
3 years ago
What I the Wannnsjsusbevdyx
Arada [10]
I have no idea what that is, but all of your answers right
3 0
3 years ago
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Not only did Skid get shot out of a cannon when he was a clown in the circus, but he was also launched into the air by a vertica
tiny-mole [99]

Answer:

v = 16.11 m / s

Explanation:

For this exercise we must use the principle of conservation of energy. We set a reference system on the part of the platform without elongation

starting point. When the spring is compressed

        Em₀ = K_e + U = ½ k x² + m g x ’

final point. The point where it leaves the platform

        Em_f = K = ½ m v²

energy is conserved

         Em₀ = Em_f

         ½ k x² + m g x ’= ½ m v²

         v² = \frac{k}{m}  x² + g x

let's calculate

         v² = \frac{8700}{55}  1.25² + 9.8 1.25

         v² = 247.159 + 12.25 = 259.409

         v = 16.11 m / s

8 0
2 years ago
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