Question

Calculate how to prepare 250.00 ml of approximately 1.0 m hcl solution from the 2.5 m hcl solution. show your work.

Answer 1

Answer: Add 150 ml of water to 100 ml of 2.5 M stock solution.

Explanation: According to the neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = 2.5 M

$V_1$ = volume of stock solution = ?

$M_2$ = molarity of desired solution = 1.0 M

$V_2$ = volume of desired solution = 250 ml

Now put all the given values in the above law, we get the volume of stock solution.

$(2.5M)\times V_1=(1.0M)\times (250ml)$

$V_1=100ml$

Therefore, 100 ml of 2.5 M of stock solution is taken and 150 ml of water is added to make the volume to 250 ml.

Answer 2

250.00 mL) x (1.0 M ) / (2.5 M) = 100 mL

So take 100 mL of 2.5 M HCl and dilute it to 250 mL.